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2 years ago

6

Bill cut out 6 squares and 8 circles.He divided the cutouts into groups so that the same number of squares and circles were in e

ach group. Which is the greatest number of groups he could have made?

1 answer:

timama [110]2 years ago

7 0

Answer:

hello hola sisters hermanas

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Hamburger sells 3 pounds for six dollars if Samantha 510 pounds of hamburger how much will she pay

Lina20 [59]

I believe you meant to say that if Samantha bought 510 pounds of hamburger, how much will she pay?

Now from the information we already have, we know that 3 pounds of hamburger will cost 6 dollars.

The next thing we need to know is how much one pound of hamburger will cost. This will help us calculate how much the rest will cost.

we now form an equation to assist us.
3 = 6
1= x

(where x represents the unknown price of one pound of hamburger)

Now we must cross-multiply:

3 * x = 6 x 1

3x = 6

x = 6/3

x = 2

therefore one pound of hamburger costs 2 dollars.

Now, If one pound costs 2 dollars, how about 510 pounds?

We simply multiply: 510 x 2 = 1,020

Therefore Samantha will pay 1, 020 dollars for 510 pounds of hamburger.

5 0

3 years ago

A student draws several cards from a deck of 10 unique cards.

egoroff_w [7]

Answer:

There are 210 different ways that 4 cards can be drawn.

There are 252 different ways that 5 cards can be drawn.

There are 120 different ways that 7 cards can be drawn.

Step-by-step explanation:

Use the combination formula

10C4 =210

10C5 = 252

10C7 = 120

6 0

2 years ago

Show work please thank you

Alenkinab [10]

Hey there!:)

b1+b2
--------- x h =area
2

(3+5)/2h=area

8/2h=area

4(2)=area
area= 8ft squared (this is your answer)

Hope this helps! Let me know if you need more help:)

8 0

2 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago

Can someone help with number 18 (the scavenger hunt)? I'll give Brainliest

erik [133]

I basically converted them all into decimals and rounded
Team 1- 0.75
Team 2- 0.8
Team 3- 0.775
Team 4- 0.825
Team 5- 0.725
Team 6- 0.7625
Team 7- 0.7875
Team 8- 0.8125
Team 4 collected the most
Team 5 collected the least

6 0

3 years ago