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3 years ago

Please help me with this question

Mathematics

1 answer:

vichka [17]3 years ago

5 0

Write the ratio out.

Number of hands Betty won : Number of hands Adam won

5:20

Both can be simplified by the common factor of 5.

1:4 is the solution.

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Simplify the expression: -5(2x - 5)

OverLord2011 [107]

Answer:

-10x+25

Step-by-step explanation:

−5(2x−5)

=(−5)(2x+−5)

=(−5)(2x)+(−5)(−5)

=−10x+25

6 0

2 years ago

The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%

vagabundo [1.1K]

Answer:

1) $\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

2) $p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

$\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}$

Where O rpresent the observed values and E the expected values.

State the null and alternative hypothesis

Null hypothesis: The distribution is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

$E = \% Grand total$

$E_{Catfish}=500*0.3=150$

$E_{Bass}=500*0.15=75$

$E_{Bluegill}=500*0.4=200$

$E_{Pike}=500*0.15=75$

Part 1: Calculate the statistic

$\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

$\chi^2 =16.313$

Calculate the critical value

First we need to calculate the degrees of freedom given by:

$df= (categories-1)=(4-1)= 3$

Since the confidence provided is 95% the significance would be $\alpha=1-0.95=0.05$ and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be $\chi^2_{crit}=7.815$

We can calculate also the p value:

$p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

5 0

2 years ago

What is the circumference of the following circle r = 1

strojnjashka [21]

Answer: C≈6.28

Step-by-step explanation:

C=2π r=2· π ·1≈6.28319

Therefor, the answer is 6.28

* hopefully this helps:)Mark me the brainliest:)

7 0

2 years ago

Read 2 more answers

Sixty people can receive a piece of pizza if 5 pizzas are purchased . How many people can receive a piece of pizza if 7 pizzas a

mel-nik [20]

There will be 84 people if you get 7 pizza’s

6 0

3 years ago

Umm like can someone help me pls I need this answered ASAP thx

Ostrovityanka [42]

To find the x-intercept, substitute in
0
0
for
y
y
and solve for
x
x
. To find the y-intercept, substitute in
0
0
for
x
x
and solve for
y
y
.
x-intercept(s):
(
5
,
0
)
(
5
,
0
)
y-intercept(s):
(
0
,
−
15
)

6 0

2 years ago

Read 2 more answers