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Mashutka [201]
3 years ago
15

Plz show your work

Mathematics
2 answers:
andrew11 [14]3 years ago
5 0

Answer:

9/5 (-8) > = F > = 9/5 (157)

Step-by-step explanation:

A. -40>= 5/9F - 32

-40+32>= 5/9F

9/5(-8) >= F

B. 125 <= 5/9F - 32

125+32 <= 5/9F

9/5(157) <= F

9/5 (-8) >= F >= 9/5 (157)

leonid [27]3 years ago
3 0

Answer:

  • Negative forty is less than five ninths times the quantity F minus thirty two.
  • Five ninths times the quantity F minus thirty two is less than one hundred twenty five.

Step-by-step explanation:

<u>Conversion equation:</u>

  • C = 5/9*F - 32

<u>We need to convert this inequality:</u>

  • -40C < T
  • T < 125C

<u>Replace T with the expression above:</u>

  • -40 <  5/9*F - 32 or 5/9*F - 32 < 125

Correct choice is C

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Please help I don’t know if I’m doing this correctly
solmaris [256]

Answers:

  1. Exponential and increasing
  2. Exponential and decreasing
  3. Linear and decreasing
  4. Linear and increasing
  5. Exponential and increasing

=========================================================

Explanation:

Problems 1, 2, and 5 are exponential functions of the form y = a(b)^x where b is the base of the exponent and 'a' is the starting term (when x=0).

If 0 < b < 1, then the exponential function decreases or decays. Perhaps a classic example would be to study how a certain element decays into something else. The exponential curve goes downhill when moving to the right.

If b > 1, then we have exponential growth or increase. Population models could be one example; though keep in mind that there is a carrying capacity at some point. The exponential curve goes uphill when moving to the right.

In problems 1 and 5, we have b = 2 and b = 1.1 respectively. We can see b > 1 leads to exponential growth. I recommend making either a graph or table of values to see what's going on.

Meanwhile, problem 2 has b = 0.8 to represent exponential decay of 20%. It loses 20% of its value each time x increases by 1.

---------------------

Problems 3 and 4 are linear functions of the form y = mx+b

m = slope

b = y intercept

This b value is not to be confused with the previously mentioned b value used with exponential functions. They're two different things. Unfortunately letters tend to get reused.

If m is positive, then the linear function is said to be increasing. The line goes uphill when moving to the right.

On the other hand if m is negative, then we go downhill while moving to the right. This line is decreasing.

Problem 3 has a negative slope, so it is decreasing. Problem 4 has a positive slope which is increasing.

7 0
2 years ago
A large university accepts 70% of the students who apply. Of the students the university accepts 25% actually enroll if 20,000 s
Andru [333]

Answer:

3500 students actually enroll

Step-by-step explanation:

20000*0.7*.25=3500

6 0
3 years ago
Read 2 more answers
8x-3x=5x^2 show work
eimsori [14]

8x-3x=5x^2\\5x=5x^2\\x=x^2\\x=1

6 0
4 years ago
Read 2 more answers
1. Find the area of the shaded region. Use 3.14 for pie.<br> 8 cm<br> 8 cm
Tju [1.3M]

Answer:

200.96

Step-by-step explanation:

3.14 times 8 times 8 is 200.96

8 0
3 years ago
Assume the random variable X is normally distributed with mean 53 and standard deviation of 6. Find the 9th percentile
satela [25.4K]

Answer:

<em>The 9th percentile of X is 44.96</em>

Step-by-step explanation:

<u>Percentiles for a Normal Distribution</u>

The standard normal distribution can be used for computing percentiles. For example, the median is the 50th percentile being the center value, the first quartile is the 25th percentile, and so on.

To compute percentiles of a normal distribution we can use the formula

X=\mu+z\sigma

Where \mu is the mean, \sigma is the standard deviation of the variable X, and z is the z-score value from the standard tables

The value of X can also be directly obtained from digital tables included in math packages and tools like Excel.

The Excel NORM.INV Function calculates the inverse of the cumulative Normal Distribution Function for a given value of p, \mu and \sigma.

We'll use the values

p=9\%=0.09,\ \mu=53, \ \sigma=6

NORM.INV(0.09,53,6) results in 44.96 which means the 9th percentile of X is 44.96

We could have used the standard normal distribution, which only needs the value of p

NORM.S.INV( 0.09 )=-1.34

That is the value of z, we now apply the formula

X=\mu+z\sigma

X=53+(-1.34)\cdot 6=44.96

We get the very same result as before

6 0
3 years ago
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