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Mashutka [201]
3 years ago
15

Plz show your work

Mathematics
2 answers:
andrew11 [14]3 years ago
5 0

Answer:

9/5 (-8) > = F > = 9/5 (157)

Step-by-step explanation:

A. -40>= 5/9F - 32

-40+32>= 5/9F

9/5(-8) >= F

B. 125 <= 5/9F - 32

125+32 <= 5/9F

9/5(157) <= F

9/5 (-8) >= F >= 9/5 (157)

leonid [27]3 years ago
3 0

Answer:

  • Negative forty is less than five ninths times the quantity F minus thirty two.
  • Five ninths times the quantity F minus thirty two is less than one hundred twenty five.

Step-by-step explanation:

<u>Conversion equation:</u>

  • C = 5/9*F - 32

<u>We need to convert this inequality:</u>

  • -40C < T
  • T < 125C

<u>Replace T with the expression above:</u>

  • -40 <  5/9*F - 32 or 5/9*F - 32 < 125

Correct choice is C

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Simplify (3x − 5) − (4x + 6).
irinina [24]

(3x − 5) − (4x + 6)

Pretend that there is a 1 in front of the first bracket.

Pretend that there is a -1 in front of the second bracket.

Multiply the first bracket by 1

(1)(3x)=3x, (1)(-5)=-5

Multiply the second bracket by -1

(-1)(4)=-4, (-1)(6)=-6

3x-5-4x-6

3x-4x-5-6 ( combine like terms)

-x-11

Answer: -x-11 or -11-x

3 0
3 years ago
STOP!
maksim [4K]

1. you would take 36×1/4 and then it would equal 9

2. you would take 24×1/4 and then it would equal 6

3 0
3 years ago
What is the pre-image vertex A’ if the rule that created the image is r y-axis (X,Y) (-x,y)
Lapatulllka [165]

Answer:

its A=(-4,2)

Step-by-step explanation:

4 0
3 years ago
The box and whiskers plot represents the results of the same math test being given to two different classes. According to the bo
densk [106]

Answer: Answer A: Both classes have a range of 45

Step-by-step explanation:

above the two graphs we can see a number line ranging from 50-100

bellow that, we can see 2 box and whisker plots, one for second period and one for fourth period. the larger rectangular boxes show all the number results, the line in between them states the average result. Both lines have starting points at 55 and ending points at 100.

100-55=45   45 being the range. Since 2nd and 4th both share the same range answer A could possibly be correct

B is wrong because 2nd period has a median of 90

C is wrong because no periods have a median of 100

D is wrong because most of the students scored an 85+

conclusion: answer A is correct

4 0
4 years ago
Read 2 more answers
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
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