Question

These are all my points I'm desperate please help I've posted this 4 other times

Answer 1

Answer:

y = (x+3)^2 -1

Step-by-step explanation:

The vertex form of the equation is

y = a(x-h)^2 +k  where (h,k) is the vertex

The vertex is (-3,-1)

y = a(x- -3)^2 -1

y = a(x+3)^2 -1

Pick another point  (-2,0) and substitute it into the equation

0 = a(-2+3)^2 -1  to find a

0 =a(1)^2 -1

0 = a-1

1 = a

y = (x+3)^2 -1

Answer 2

Answer:

y = (x + 3)² - 1

y = x² + 6x + 8

Step-by-step explanation:

Vertex: (-3,-1)

y-intercept: (0,8)

y = a(x - -3)² - 1

y = a(x + 3)² - 1

8 = a(0 + 3)² - 1

9a = 9

a = 1

y = (x + 3)² - 1

y = x² + 6x + 8