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ss7ja [257]
3 years ago
11

Can someone pls help me 2-7 thank u :)

Mathematics
2 answers:
kolbaska11 [484]3 years ago
8 0
2. 27
3. 13
4. 35
6. 22
7. 60

I was unable to help with 5 because of the plot box!! Hope this helps
miskamm [114]3 years ago
7 0
2 is 27!!!!!!!!!!!!!!
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What is the solution to the equation x + 11 = 57? (Input a whole number only.) Numerical Answers Expected! Answer for Blank 1:
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X + 11 = 57 
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3 years ago
In the parallelogram below, W = ?
Ivenika [448]
All angles in a triangle add to 180
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2.
mihalych1998 [28]
Answer:
False

Explanation:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.

For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
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The population of a small town in central Florida has shown a linear decline in the years 1992-2000. In 1992 the population was
wlad13 [49]

Answer:

  • P = -390t +48,000
  • P = 43,710 in 2003

Step-by-step explanation:

A) We are given two pairs of (t, P): (0, 48000), (8, 44880). We can use these with the 2-point form of the equation of a line:

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  P = (44880 -48000)/(8 -0)(t -0) +48000

  P = -3120/8t +48000

  P = -390t +48000

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B) In 2003, t = 11, so we have ...

  P = -390(11) +48000 = 43710

The population in 2003 is predicted to be 43,710.

7 0
3 years ago
The equation 12x² + 4kx + 3 = 0 has real and equal roots, if
sleet_krkn [62]

Answer:

k=\pm3

Step-by-step explanation:

[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant \Delta = b^2-4ac (or, if b is an even number, 1/4 of it) is zero.

<u>I see it! I see it!</u>

Stare at it for a while. First term is 3(2x)^2, third term is 3(1)^2, we are missing a double product, but we can play with k. For the LHS to be 3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3 you just need 4k= \pm12 \rightarrow k=\pm3.

<u>I don't see it...</u>

Then number crunching it is. Set the discriminant to 0, solve for k

\frac{\Delta}4 = 4k^2-12\cdot 3 =0 \rightarrow 4k^2=36 \\k^2 = 9 \rightarrow k=\pm3

8 0
2 years ago
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