3/11 x 5/11
15/121 would be the probability. I am not sure if it can simplify any more! :)
The answer would be 7,433,700
Answer:
The distance between them changing after 10 minutes will be 9.553 mph.
Step-by-step explanation:
The paths of two runners cross at a stop sign (O). One runner is heading south at a constant rate of 6.5 miles per hour towards A while the other runner is heading west at a constant rate of 7 miles per hour towards B.
So, after 10 minutes the first runner covers a distance of miles and the second runner covers a distance of miles.
Therefore, after 10 minutes their distance will be miles.
Now, the distance between them is given by
AB² = OA² + OB²
Now, differentiating this equation with respect to time t (in hours) we get
⇒
⇒
⇒ mph.
Therefore, the distance between them changing after 10 minutes will be 9.553 mph. (Answer)