Answer:
C ) y + 3 = 1/4 ( x + 4 )
Explanation:
Given that you did not include the "given line", I can help you by explaning how to solve this kind of problems, step by step.
The procedure is based of the property of perpendicular lines: the product of the slopes of perpedicular lines is negative 1.
If you call m1, the slope of a line and m2 the slope of a perpendicular line, then:
m1 * m2 = - 1, and you can solve for either m1 or m2:
m1 = - (1 / m2)
m2 = - (1 / m1).
With that this is the procedure:
1) find the slope of the "given line". Name it m1.
2) find the slope of the perpendicular line:
m2 = - (1 / m1).
3) Use the equation of the line with the point (x1,y1) and slope m2
y - y1
-------- = m2
x - x1
4) In this case the point is (-4, - 3)=> x1 = - 4, y1 = - 3
=>
y - (-3)
---------= m2
x - (-4)
=> y + 3 = m2 * (x + 4)
=> y = m2*x + m2 * 4 - 3
Which is the point-slope form. You only have to replace m2 with the slope value of the perpendicular line, which I already explained that you find as m2 = (-1/m1).
Taking that the other line has m1 = - 4 so m2 = 1/4
y = (1/4)x + (1/4) * 4 - 3
y = (1/4) (x +4) - 3
y + 3 = (1/4) (x + 4) and answer is:
C ) y + 3 = 1/4 ( x + 4 )
F(n) = 11
g(n) = (3/4)^(n - 1)
To create a geometric sequence. multiply f(x) and g(x)
an = f(x)g(x) = 11(3/4)^(n - 1)
9th term is 11(3/4)(9 - 1) = 11(3/4)^8 = 11(0.100) = 1.101
Answer:
Look for the y-intercept where the graph crosses the y-axis. Look for the x-intercept where the graph crosses the x-axis. Look for the zeros of the linear function where the y-value is zero.
Step-by-step explanation:
The slope is mx+b so find two points in the graph and use y-rise/x-run
