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Ksju [112]
3 years ago
10

The distance around a racetrack is 2/3 of a mile. How many laps must you run around the track if you want to run six miles?

Mathematics
1 answer:
Sergio039 [100]3 years ago
4 0

You must run around the track 9 times.

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What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4,
zheka24 [161]
Answer: C ) y + 3 = 1/4 ( x + 4 )

Explanation:

Given that you did not include the "given line", I can help you by explaning how to solve this kind of problems, step by step.

The procedure is based of the property of perpendicular lines: the product of the slopes of perpedicular lines is negative 1.

If you call m1, the slope of a line and m2 the slope of a perpendicular line, then:

m1 * m2 = - 1, and you can solve for either m1 or m2:

m1 = - (1 / m2)

m2 = - (1 / m1).

With that this is the procedure:

1) find the slope of the "given line". Name it m1.

2) find the slope of the perpendicular line:

    m2 = - (1 / m1).

3) Use the equation of the line with the point (x1,y1) and slope m2

y - y1
-------- = m2
x - x1

4) In this case the point is (-4, - 3)=> x1 = - 4, y1 = - 3

=>

y - (-3)
---------= m2
x - (-4)

=> y + 3 = m2 * (x + 4)

=> y = m2*x + m2 * 4 - 3

Which is the point-slope form. You only have to replace m2 with the slope value of the perpendicular line, which I already explained that you find as m2 = (-1/m1).

Taking that the other line has m1 = - 4 so m2 = 1/4

      y = (1/4)x + (1/4) * 4 - 3

      y = (1/4) (x +4) - 3

      y + 3 = (1/4) (x + 4) and answer is: C ) y + 3 = 1/4 ( x + 4 )



7 0
3 years ago
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Write using exponent (-2) (-2) (-2) (-2)
poizon [28]
It would be
( - 2) {}^{4}
3 0
3 years ago
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Given the functions f(n) = 11 and g(n) = (3/4)n _ 1, combine them to create a geometric sequence, an, and solve for the 9th term
trapecia [35]
F(n) = 11
g(n) = (3/4)^(n - 1)

To create a geometric sequence. multiply f(x) and g(x)
an = f(x)g(x) = 11(3/4)^(n - 1)

9th term is 11(3/4)(9 - 1) = 11(3/4)^8 = 11(0.100) = 1.101
5 0
3 years ago
Which graph shows a function with a zero of –5?
Vedmedyk [2.9K]

Answer:

Look for the y-intercept where the graph crosses the y-axis. Look for the x-intercept where the graph crosses the x-axis. Look for the zeros of the linear function where the y-value is zero.

Step-by-step explanation:

8 0
3 years ago
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PLEASE HELP ASAP!! WILL MARK BRAINLIEST
KATRIN_1 [288]
The slope is mx+b so find two points in the graph and use y-rise/x-run 
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