I need some help on this problem

Mathematics

1 answer:

wolverine [178]2 years ago

5 0

437 is your answer
______
3)131.1
- 12
____
11
- 9
______
21
- 21
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0

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Is 46 greater or less than -79

Alona [7]

Answer:

46 is greater than -79

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2 years ago

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3) Ashley uses the two points on the coordinate plane to represent the location of her house and the public library. Each unit o

Aleonysh [2.5K]

By counting grid squares, we see the library is 5 miles north and 6 miles east of Ashley's house. Using the Pythagorean theorem, we can find the straight-line distance to be
.. d = √(5^2 +6^2)
.. = √(25 +36)
.. = √61 . . . . . miles
.. ≈ 7.81 . . . . miles

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2 years ago

3. Kevin went to the nursery and bought a 5 ft tall tree. After planting the tree, Kevin made a table to record the height, h, o

Rina8888 [55]

Answer:

uh where's the rest of the question?

Step-by-step explanation:

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2 years ago

What is the midpoint of the line segment with endpoints (1,-6) and (-3,4)?

kirill115 [55]

Answer:

(-1,-1)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2

(1+-3)/2 = -2/2 = -1

To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2

(-6+4)/2 = -2/2 = -1

(-1,-1)

8 0

2 years ago

For the function, f(x)=(9x+7)/(2x+4)

AVprozaik [17]

A. $f(x)=\frac{9x+7}{2x+4}\\f'(x)=\frac{(9)(2x+4)-(9x+7)(2)}{(2x+4)^2}\\f'(x)=\frac{(18x+36)-(18x+14)}{(2x+4)(2x+4)}\\f'(x)=\frac{22}{4x^2+16x+16}\\f'(x)=\frac{11}{2x^2+8x+8}\\\frac{11}{(2x+4)(x+2)}=0\\\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty$ - There are no critical points because the graph is neither continuous nor smooth. There is a discontinuity at x = 2.

B. $\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty$ - The absolute maximum is f(lim⇒-2_-) = infinity. The absolute minimum is f(lim⇒-2_+) = -infinity. This applies to the interval [-10, 7].

C. $f(x)=\frac{9x+7}{2x+4}\\f(0)=\frac{9(0)+7}{2(0)+4}\\f(0)=\frac{7}{4}\\f(0)=1.75\\f(5)=\frac{9(5)+7}{2(5)+4}\\f(5)=\frac{45+7}{10+4}\\f(5)=\frac{52}{14}\\f(5)=\frac{26}{7}\\f(5)=3.714$ - The absolute maximum is f(5) = 26/7 or 3.714. The absolute mimimum is f(0) = 1.75. This applies to the interval [0, 5]. Proof: graph f(x) at [0, 5] on a graph or graphing calculator.

5 0

2 years ago