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lozanna [386]
2 years ago
10

Analyze the diagram below and answer the question that follows.

Mathematics
2 answers:
babunello [35]2 years ago
6 0

Shaded part means the yellow part

  • The two sets are S and Y.
  • The centre intersection part is A\cap
  • All the areas occupied by both sets is AUB .

Rest part :-

\\ \sf\longmapsto E-AUB=(AUB)^c

Anna [14]2 years ago
6 0

Answer:

  • D. (S∪T)^C

Step-by-step explanation:

<u>The shaded region is outside of combined regions S and T but within the set of U:</u>

  • U - S∪T = (S∪T)^C

Correct choice is D

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Which triangle is ​△MNO​ similar to and why? △MNO is similar to △GHK by ​ AA Similarity Postulate ​. ​△MNO​ is similar to △DEF b
andrew11 [14]
<span>MNO is similar to GHK by AA Similarity Postulate

   Let's start by listing each triangle and the measurements of all three angles. For each triangle, we've been given the measurements of 2 of the angles and the 3 angle will simply be 180 minus the other 2 angles. I assume you can do the subtraction, so I'll simply list each triangle with all three angle measurements.
 NMO: 79, 22, 79
 GHK: 79, 79, 22
 PQR: 20, 79, 81
 DEF: 82, 22, 76
   And the triangles NMO and GHK are similar to each other since they have the same angles. The order really doesn't matter since it's OK for similar triangles to be rotated or reflected. The key thing to remember in a triangle is that if you've been told what 2 of the angles are, you also know what the 3rd angle is since the sum of the angles of a triangle will always be 180.
So the answer is:
 MNO is similar to GHK by AA Similarity Postulate"</span>
7 0
4 years ago
If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

8 0
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Can someone help me ​
Yanka [14]

Answer:

C

Step-by-step explanation:

if right mark brainlyest

7 0
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How many tutors does the academy need if it has 120 students ?
kakasveta [241]
120 / 72 = 1 2/3

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The academy needs 10 tutors.
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valentinak56 [21]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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