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Andre45 [30]
3 years ago
12

Someone refresh me on constant of proportionality, forgot all about it!!!!

Mathematics
1 answer:
MAXImum [283]3 years ago
3 0
A cycle, that is in the consideration of the earth and also help the combinations of things
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Plz helpppppppppppppppppppppppppppppppppppp quick
Tanzania [10]

Answer:

B. 8

Step-by-step explanation:

6, 15, 7, 5, 11, 11, 8

5, 6, 7, 8, 11, 11, 15

The middle number is 8.

4 0
3 years ago
Read 2 more answers
Which table shows a non linear relationships between x and y
bazaltina [42]

Answer:

both of them thats the answer

Step-by-step explanation:

7 0
2 years ago
A dealer offers a $35,000 car with a downpayment of $3,000 and 65 easy monthly payments of $539.99. How much monthly interest ra
m_a_m_a [10]

Answer:

9.68%

Step-by-step explanation:

cost of car = $35,000

down payment = $3,000

number of monthly instalments= $65

amount in every monthly instalment= $539.99

total monthly payment= 65×539.99= 35099.35

amount to be paid apart from downpayment= $35,000-3000= 32,000

therefore total interest paid in 65 months= 35099.35-3200= $3099.35

now, monthly interest rate r= \frac{3099.35}{32,000}\times100

⇒ r= 9.68%

5 0
2 years ago
Read 2 more answers
Given that f(x) = x2 + 6x – 2, g(x) = x – 7, and h(x) = x + 4 find each function.
choli [55]

Answer:

A) x² + 7x - 9

Step-by-step explanation:

Deduct\Add each like-term to arrive at your answer.

3 0
3 years ago
When a fair coin is flipped, what is the chance of getting about 50% heads- specifically between 40% and 60% heads for n=10 flip
aleksklad [387]
At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide
3 0
2 years ago
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