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Karo-lina-s [1.5K]
3 years ago
6

CAN SOMEONE PLEASE HELP ME????

Mathematics
1 answer:
Deffense [45]3 years ago
4 0
<span>Luis has 5 cans of soda. He will buy more cans of soda from the store. The store has 12 cases in stock and each case contains 24 cans of soda. The store will not sell partial cases. The function that models the number of cans Luis will have after his purchase is f(c) = 24c + 5.

What is the practical domain and range of the function? 

5 is the initial number of cans Luis has on hand.  To this 5 we add 24 times c, where c represents the # of cases (not cans).   Thus, if he buys 1 case, he will have 5+24(1), or 29, cans on hand.

c represents the number of cases he buys.  He cannot buy a neg. number of cases, altho he could theoretically buy 0 cases by not going to the store.

Thus, the domain is {integers only, ranging from 1 to infinity}

The smallest number of cans this guy would have is 5, so the range is

{integers from 5 up}</span>
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olganol [36]

Answer:

(36 - 16)

((20)

‍♀️ its simple

8 0
3 years ago
A regulation-size women's basketball has a diameter of 9.07 inches. What is the surface area of the basketball? Use 3.14 for π a
aleksley [76]

Answer:

258.3 sq inches

Step-by-step explanation:

Use the sphere surface area formula, SA = 4\pir²

The diameter is 9.07 inches, so the radius is 4.535 inches.

Plug in 3.14 as pi and 4.535 as r, and solve:

SA = 4\pir²

SA = 4(3.14)(4.535)²

SA = 258.3

So, the surface area is approximately 258.3 sq inches

5 0
3 years ago
Please help! I need this now who ever gets this first will get a brainlest
Furkat [3]

Answer:

the cost of 0 caramel bags

8 0
3 years ago
Read 2 more answers
Nathan deposit seven Knights of his allowance into his savings account he spent the remaining amount or 2.50 how much did Nathan
evablogger [386]

Total allowance = 11.25

amount to be deposited: 11.25 * 7/9 = 78.75/9 = 8.75

hope this helps.

4 0
3 years ago
Find the vertex, focus, directrix, and focal width of the parabola. (5 points)
Anarel [89]

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf -\cfrac{1}{20}x^2=y\implies \cfrac{x^2}{-20}=y\implies x^2=-20y\implies (x-0)^2=-20(y-0) \\\\\\ (x-\stackrel{h}{0})^2=4(\stackrel{p}{-5})(y-\stackrel{k}{0})

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,

vertex is at (0,0)

the focus point is "p" or 5 units down from there, namely at (0, -5)

the directrix is "p" units on the opposite direction, up, namely at y = 5

the focal width, well, |4p| is pretty much the focal width, in this  case, is simply yeap, you guessed it, 20.

8 0
3 years ago
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