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NARA [144]
3 years ago
5

you are lying 120 ft away from a tree that is 50 feet tall you look up at the top of the tree approxmaelty how far is your head

from the top of the tree in a straight line

Mathematics
1 answer:
Pepsi [2]3 years ago
5 0
Check the picture below.

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Select all true statements
pychu [463]

Answer:

B,C,E are right statements

6 0
3 years ago
Distribute and combine like terms. Please show all of your work.<br><br> -5(3x + 7) - 4(x - 4) + 11
Varvara68 [4.7K]

For this case we have the following expression:

-5 (3x + 7) -4 (x-4) +11

For simplicity we follow the steps:

We apply distributive property to the terms within the parenthesis, bearing in mind that:

- * + = -\\- * - = +\\-15x-35-4x + 16 + 11 =

We add similar terms taking into account that equal signs are added and the same sign is placed, while different signs are subtracted and the sign of the major is placed.

-15x-4x-35 + 16 + 11 =\\-19x-8

ANswer:

-19x-8

5 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (2, 3) and (–2, 6)? A. -3/2 B. -3/4 C.3/4 D. 0
Alisiya [41]
Simple...

you have: (2,3) and (-2,6)

Using \frac{ y_{1}-  y_{2} }{ x_{1} - x_{2} }-->>

\frac{3-6}{2--2} = -\frac{3}{4}

Thus, your answer.
8 0
3 years ago
Read 2 more answers
A forester studying the effects of fertilization on certain pine forests in the Southeast is interested in estimating the averag
ahrayia [7]

Answer:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(ZStep-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the area of a population, and for this case we know the distribution for X is given by:

X \sim N(M,4)  

Where \mu=M and \sigma=4

We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(Z

8 0
3 years ago
Find two numbers with a sum of 20 and a difference of 14
shepuryov [24]
2 and 7 r the answer

3 0
3 years ago
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