Yall im almost done pls HELP
1 answer:
Answer :
61 degrees
Step-by-step explanation :
==>Given ∆MNO,
MO = 18,
MN = 6
m<O = 17°
==>Required:
Measure of <N
==>SOLUTION:
Use the sine formula for finding measure of angles which is given as: Sine A/a = Sine B/b = Sine C/c
Where,
Sine A = 17°
a = 6
Sine B = N
b = 18
Thus,
sin(17)/6 = sin(N)/18
Cross multiply
sin(17)*18 = sin(N)*6
0.2924*18 = 6*sin(N)
5.2632 = 6*sin(N)
Divide both sides by 6
5.2632/6 = sin(N)
0.8772 = sin(N)
sin(N) = 0.8772
N = sin^-1(0.8772)
N ≈ 61° (approximated)
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HI there i know this is way later than you needed it but I though i would give you the correct answer which is B x=±√15/3 i also have proof from an old test that my answer is right.
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