7(x+y) because their both factors of 7
Answer: 32x^11 y^6
If you are still confused just let me know i will do it step by step :)
Answer:
(3,1) and (3,2)
Step-by-step explanation:
We are given that a relation
{(0,0.5),(0.5,1),(3,1),(1,6),(3,2)}
We have to find that ordered pair which causes this relation not to be a function.
We know that
Function: It is a mapping between two non- empty set A and B.
Every element of set A has unique image in set B.
One element of set A can not have two or more images in set B.
Two or more elements of set A have same images in set B.
In given relation images of 3 are 1 and 2 which is not possible if a relation is function because one element can not have two or more images.
The ordered pair (3,2) and (3,1) cause this relation not to be a function because image of 3 are 1 and 2 which is not possible .
Answer: (3,1) and (3,2)
The answer to that question is 44 hope this helps :-)
