The answer is 33
3(-2)^2+4(-2)+5
-6^2+ (-8) + 5
36 + (-8) + 5
28+5
33
Answer:
(y - -2) (6 - 3) - (2 - -2) (x - 3) = 0
6y + 2 - 3y - 6 -2x +6 +2x +6 = 0
3y +8 =0
3y = -8
y = -8/3
Step-by-step explanation:
2.99948138 is the answer ur welcome
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the mean amount of time that teens spend online each week.
Number of sample, n = 41
Mean, u = 43.1 hours
Standard deviation, s = 5.91 hours
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
43.1 ± 1.645 × 5.91/√41
= 43.1 ± 1.645 × 0.923
= 43.1 ± 1.52
The lower end of the confidence interval is 43.1 - 1.52 =41.58
The upper end of the confidence interval is 43.1 + 1.52 =44.62
Therefore, with 90% confidence interval, the mean amount of time that teens spend online each week is between 41.58 and 44.62
The result follows directly from properties of modular arithmetic:
That is,
means we can write 
for some integer 
. Then
and taken mod 12, the first term goes away, so
etc
