1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dafna11 [192]
3 years ago
7

What is y = 6/3x - 2 in standard form?

Mathematics
1 answer:
umka2103 [35]3 years ago
7 0
Y = 6/3x - 2
Just move x to the other side, 
y - 6/3x = -2
Multiply by -1, 
6/3x - y = 2

In short, Your Answer would be 6/3x - y = 2 or 2x - y = 2

Hope this helps!
You might be interested in
NEED HELP HERE PLEASE
loris [4]
1. The answer is C. cos180=-1, sin180=0. 2*(cos180+i*sin180)=2*(-1+0)=-2. Check every other answer, none of which gets -2. 

2. The answer is C. cos270=0, sin270=-1. (You can draw out these angles to see). 2*(cos270+i*sin270)=2*(0-i)=-2i, as desired. Other choices don't work.

3. Answer A. Modulus of z is \sqrt(6^2+(-6)^2)=6*\sqrt(2). <span>The </span>angle<span> of the </span>point<span> on the complex </span>plane<span> is the </span>inverse tangent<span> of the complex portion over the real portion. Theta=arctan(-6/6), and arctan(-1)=-pi/4, so theta=-pi/4=-pi/4+2pi=7pi/4. So A is the correct answer.

4. The answer is A. As above, cos270=0, sin270=-1. 3(cos270+sin270*i)=3*(0-i)=-3i. This problem is similar to question 2.

5. </span>z1 = 7(cos 40° + i sin 40°), and z2 = 6(cos 145° + i sin 145°). z1*z2=7*6*(cos 40° + i sin 40°)*(cos 145° + i sin 145°)=42*(cos40*cos145-sin40*sin145+i*sin40*cos145+i*sin145*cos40). Use formula for sum/difference formula of cosines, cos40*cos145-sin40*sin145=cos(40+145)=cos185. Again, sin40*cos145+sin145*cos40=sin(40+145)=sin185. The answer is <span>42(cos 185° + i sin 185°).</span>
6 0
3 years ago
I need help with this
iragen [17]
The expression would be: 11.5-1 1/2x
x represents the number of weeks she would cut her hair off.

Please vote my answer brainliest. thanks!
7 0
3 years ago
Read 2 more answers
Two objects are moving along separate linear paths where each path is described by postion, d, and time, t. The variable d is me
fiasKO [112]
Linear equation:  d = m t + b
If the graph of the position of the second object is parallel to d = 2.5 t +2.2, than m = 2.5
t = 0, d = 1
1 = 2.5 · 0 + b
b = 1
Answer: A ) d = 2.5 t + 1
3 0
3 years ago
Read 2 more answers
-10x - 135 = 117 + 2x<br><br> A. -18<br><br> B. 22<br><br> C. 25<br><br> D. -21
Mice21 [21]

la respuesta que encontré yo fue la c

5 0
3 years ago
Find three points that belong to the graph and use them to sketch the graph of the equation: y = −3 −x
dalvyx [7]

Answer:

To find a point that belongs to the graph, you have to assume the value of one variable and compute the other one. For example, if x = 0, then y = -3 -0 = -3. Similarly:

x   y

0   -3

1    -4

2    -5

To make the graph, locate the previous points on the coordinate plane and then draw the line that passes through them (see figure attached)

6 0
3 years ago
Other questions:
  • The base of a right pentagonal prism has an area of 20 square inches. if the prism has an altitude of 8 inches, determine and st
    5·1 answer
  • 1. The following problem ropresents a population of bacteria. P(t)=360(2)^t where toquals time in hours. How many bacteria are p
    13·2 answers
  • How do I solve 2x^3-32x=0
    9·1 answer
  • Benny is 12 years old. He is currently 200% of his sisters age. What percent of Benny's age will his sisters age be in 4 years?
    10·1 answer
  • The interior angles formed by the sides of a pentagon have measures that sum to 540°. What is the measure of angle B?
    6·2 answers
  • Find solution and show work for: (3.4^17)4
    14·1 answer
  • What is the value of x in the equation 2(x – 3) + 9 = 3(x + 1) + x?<br><br> x =
    5·1 answer
  • The expression 3(x-3) is equivalent to<br> pls help lol
    5·1 answer
  • Hey! Here’s an answer for those who have this question.
    5·1 answer
  • Please help me solve this! 2 1/3 x 1 1/2
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!