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4 years ago

Write an equation in slope intercept form for a line that goes through the point (-9,4) and is perpendicular to line Y=-3x-2

Mathematics

1 answer:

Leto [7]4 years ago

3 0

Answer:

y = (1/3)x + 7

Step-by-step explanation:

The slope of a line perpendicular to the given line y = -3x - 2 would have to be the negative reciprocal of the slope of the given line:

or, in other words,

the negative reciprocal of -3. That would be +1/3.

Starting with the slope-intercept form of the equation of a straight line, we have:

y = mx + b.

We substitute the coordinates of the given point, (-9,4), and the slope +1/3:

4 = (1/3)(-9) + b.

This simplifies to

4 = -3 + b, from which it can be easily seen that b = 7.

The desired line is y = (1/3)x + 7.

You might be interested in

−5x + By = −1, (-4, 7) : Find B

stepladder [879]

Answer:

its -3

all you gotta do is substitue the point in for x and y

x = -4

y = 7

8 0

3 years ago

What is an equation of the line that passed through (-8,2) and has slope -3/4

Vlad [161]

-3/4 * -8 = 2
-3/4x-4

3 0

3 years ago

Help I am being timed

Schach [20]

6.5x2.5=16.25
0.6x2.5=1.5
6.0x2.5=15

1.) 1.5
2.) 15
3.) 16.25

I hope that helped. Good luck!

5 0

4 years ago

Find the value of tan F rounded to the nearest hundredth , if necessary

spin [16.1K]

Using it's formula, it is found that the tangent of F is given by:

$\tan{F} = \frac{6\sqrt{85}}{85}$

<h3>How to find the tangent of an angle?</h3>

In a right triangle, the tangent of an angle is given by the length of the opposite leg divided by the length of the adjacent leg.

Researching the problem in the internet, it is found that for the <em>right triangle</em> in this problem:

The length of the opposite leg to angle F is of 6.

The length of the adjacent leg to angle F is of x.

The length of the hypotenuse is of 11.

Applying the Pythagorean Theorem, we have that:

$6^2 + x^2 = 11^2$

$36 + x^2 = 121$

$x^2 = 85$

$x = \sqrt{85}$

Considering that the tangent is the length of the opposite leg divided by the length of the adjacent leg, we have that:

$\tan{F} = \frac{6}{\sqrt{85}} \times \frac{\sqrt{85}}{\sqrt{85}} = \frac{6\sqrt{85}}{85}$

To learn more about tangent, you can take a look at brainly.com/question/24680641

7 0

3 years ago

I need help i will mark brainliest

GalinKa [24]

Answer:

-2?

Step-by-step explanation:

Multiply -1 by -4 to get 4

subtract 20 from 12 to get -8

$\frac{-8}{4}$ simplify to get -2

6 0

3 years ago