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IRISSAK [1]
4 years ago
6

Find f(A) = A^100 for A=[1 2 0 2] matrix by using Carley-Hamlton theory principles

Mathematics
1 answer:
Ymorist [56]4 years ago
5 0
A×4  = E, so A = E/4
B/4   = E, so B = 4E
C+4  = E, so C = E=4
D-4   = E, so D = E+4
and
A+B+C+D=100.

now substitute the values that  we got of A, B, C and D in the equation, to get,
(E/4) + 4E + E-4 + E+4 = 100
(E/4) + 4E + 2E = 100
(E/4) + 6E = 100
(E+24E)/4 = 100
E+24E = 100×4
25E = 400
E = 400/25
E = 16

i answered same question before too ....

<span>Hope it helps !!!</span>
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Answer:

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Step-by-step explanation:

Let

x -----> the first number

y ----> the second number

z ----> the third number

we know that

y=5x -----> equation A

z=x+100 ----> equation B

x+y+z=492 ----> equation C

Solve the system of equations by substitution

substitute equation B and equation A in equation C and solve for x

x+5x+x+100=492

7x=492-100

7x=392

x=56

<u><em>Find the value of y</em></u>

y=5x -----> y=5(56)=280

<u><em>Find the value of z</em></u>

z=x+100 ----> z=56+100=156

therefore

The numbers are 56, 280 and 156

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Step-by-step explanation:

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