Answer:

Step-by-step explanation:
A is on the same point on the x-axis as B and the same point on the y-axis as D
- Therefore, the coordinate of A is (0,0)
C is on the same point on the x-axis as D and the same point on the y-axis as B.
- Therefore, the coordinate of C is (a,a)
We are to determine the slope of the line joining A to C.


Answer:
Patel will require more orange juice =
cups
Step-by-step explanation:
Patel needs the orange juice for his family = 3 cups
He needs more orange juice = 3 cups - Sum of juice squeezed from different oranges

L.C.M. of the denominators = 660


= 
= 
Therefore, amount of orange juice required more =
cups
Answer: 
Explanation:
The equation is:

The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.
This means that we can solve separately for the two terms:

Solving the first equation:

Solving the second equation:
