<h3>
Answer: Largest value is a = 9</h3>
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Work Shown:
b = 5
(2b)^2 = (2*5)^2 = 100
So we want the expression a^2+3b to be less than (2b)^2 = 100
We need to solve a^2 + 3b < 100 which turns into
a^2 + 3b < 100
a^2 + 3(5) < 100
a^2 + 15 < 100
after substituting in b = 5.
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Let's isolate 'a'
a^2 + 15 < 100
a^2 < 100-15
a^2 < 85
a < sqrt(85)
a < 9.2195
'a' is an integer, so we round down to the nearest whole number to get 
So the greatest integer possible for 'a' is a = 9.
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Check:
plug in a = 9 and b = 5
a^2 + 3b < 100
9^2 + 3(5) < 100
81 + 15 < 100
96 < 100 .... true statement
now try a = 10 and b = 5
a^2 + 3b < 100
10^2 + 3(5) < 100
100 + 15 < 100 ... you can probably already see the issue
115 < 100 ... this is false, so a = 10 doesn't work
abcd is a parallelogram
Step-by-step explanation:
so yiu gotta like 1 angle to the 2 angle buy thats seprare from the 3 angle to the 4 angle
Answer:
x = 5/2
y = -2
Step-by-step explanation:
(1+i)² (x+yi) = 4+5i
(1+2i+i²)(x+yi) = 4+5i
(1+2i-1)(x+yi) = 4+5i
2i(x+yi) = 4+5i
2i²y + 2xi = 4+5i
-2y + 2xi = 4 + 5i
By comparing both sides,
-2y = 4
y = -2,
2x = 5
x = 5/2
The complete question in the attached figure
we know that
1) <span>The triangles that are formed in the hexagon by joining all the vertices with the center of the hexagon are all equilateral and are equal in size
therefore
the radius of the circle is equals to the length side of the regular hexagon
FE=BP--------> FE=6 cm
the answer is FE=6 cm </span>