Average rate = distance / time
distance = average rate x time
Range of distance = 2.2(1) to 2.2(3) = 2.2 to 6.6
Required range is all real numbers from 2.2 to 6.6, inclusive.
First you have to figure out the length of the track:
r is the half of the diameter:
200ft : 2 = 100ft
= 200
≈
628,31
The athlete has to run ca. 5280ft for one mile:
5280 : 628,31≈8,4
The athlete has to run 8,4 laps
Answer:
b= 2 over 7
Step-by-step explanation:
exact form b= 2 over 7
decimal form b= 0.285714
Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.
<u>Step-by-step explanation:</u>
As given by the statement in the problem,
Q may be the middle point, which cut the diagonal PA into 2 equal halves.
In rhombus, diagonals meet at right angles.
which means that PQ = QA
x+2 = 3x - 14
Grouping the terms, we will get,
3x -x = 14+ 2
2x = 16
dividing by 2 on both sides, we will get,
x = 16/2 = 8
8+2 = 3(8) - 14 = 10 = PQ or QA
Answer:
A = 200.96 sq ft
Step-by-step explanation:
formula for area of a circle: A = π·r²
A = (3.14)·(8²)
A = 64·(3.14)
A = 200.96
