3 years ago

Find the directional derivative of g(x, y) = xey − yex , 2x x − y at the point (1, 0) in the direction v = 3i + 4j

Mathematics

1 answer:

salantis [7]3 years ago

7 0

no rurio greob tryo yeu

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-6 - 3(2x + 4) = 18what’s the answer

Brrunno [24]

Answer:

$x=-6$

Step-by-step explanation:

$-6-3\left(2x+4\right)=18$

Add 6 to both sides:

$-6-3\left(2x+4\right)+6=18+6$

$-3\left(2x+4\right)=24$

Divide both sides by -3:

$\frac{-3\left(2x+4\right)}{-3}=\frac{24}{-3}$

$2x+4=-8$

Subtract 4 from both sides:

$2x+4-4=-8-4$

$2x=-12$

Divide both sides by 2:

$\frac{2x}{2}=\frac{-12}{2}$

$x=-6$

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3 years ago

What is the simplest form of the following expression?

S_A_V [24]

$\sqrt[3]{ \frac{12x ^{2} }{16y} } = \sqrt[3]{\frac{3x ^{2} }{4y} }$

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3 years ago

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The second deposit that apex savings bank received was $12,700. If apex savings bank was required to keep $571.50 on reserve, wh

vodomira [7]

$12700 \div 571.50 = 22.22$

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3 years ago

A 20-kilogram mass is attached to a spring. If the frequency of simple harmonic motion is 2/p cycles/s, what is the spring const

SVEN [57.7K]

Step-by-step explanation:

Frequency of a mass-spring system is:

f = √(k/m) / (2π)

Given f = 2/π Hz and m = 20 kg:

2/π Hz = √(k / 20 kg) / (2π)

4 Hz = √(k / 20 kg)

16 s⁻² = k / 20 kg

k = 320 kg/s²

k = 320 N/m

If the 20 kg mass is replaced with an 80 kg mass, the frequency is:

f = √(320 kg/s² / 80 kg) / (2π)

f = √(4 s⁻²) / (2π)

f = 2 Hz / (2π)

f = 1/π Hz

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3 years ago

Could someone help i'll give you 30 points just help due by midnight thanks

kap26 [50]

For number 5. X=12.5 and for number 6. X=4

Hope this helps :)

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2 years ago