Question

A triangle has a perimeter of 48" and the dimensions of each side are given as X + 3, 4x-1, 2X -3 solve for the value of X and determine the length of each side

Answer 1

In general we know perimeter is equal to sum of each side of triangle.

SO we can add all three sides to find perimeter of triangle.

SO perimeter is = x+3 + 4x - 1 + 2x - 3
                          = 7x -1

As perimeter is 48.

So we can write 7x - 1 = 48

7x - 1 = 48

On adding 1 on both sides.

7x- 1+ 1 =  48 +1

7x = 49

On dividing 7 on both sides.

$\frac{7x}{7} = \frac{49}{7}$

$x= 7$

So length of first side is = x+3 = 7+3 = 10
Length of second side = 4x - 1 = 4*7 - 1 = 27
Length of third side = 2x - 3 = 2*7 - 3 = 11

So side of triangle = 10 . 27 , 11