The following table shows the length and width of two rectangles:

1 answer:

6 0

The perimeter of a rectangle is equal to two times the sum of the length and the width.
$P=2(l+w)$

Rectangle A:
$l=3x+2 \\ w=2x-1 \\ \\
P_A=2(3x+2+2x-1)=2(5x+1)=10x+2$

Rectangle B:
$l=x+5 \\ w=5x-1 \\ \\
P_B=2(x+5+5x-1)=2(6x+4)=12x+8$

The perimeter of rectangle B minus the perimeter of rectangle A:
$P_B - P_A=12x+8-(10x+2)=12x+8-10x-2=\boxed{2x+6}$

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The picture in the attached figure

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step 1
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