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4 years ago

13

The following table shows the length and width of two rectangles:

1 answer:

gladu [14]4 years ago

6 0

The perimeter of a rectangle is equal to two times the sum of the length and the width.
$P=2(l+w)$

Rectangle A:
$l=3x+2 \\ w=2x-1 \\ \\
P_A=2(3x+2+2x-1)=2(5x+1)=10x+2$

Rectangle B:
$l=x+5 \\ w=5x-1 \\ \\
P_B=2(x+5+5x-1)=2(6x+4)=12x+8$

The perimeter of rectangle B minus the perimeter of rectangle A:
$P_B - P_A=12x+8-(10x+2)=12x+8-10x-2=\boxed{2x+6}$

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Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt

SashulF [63]

Answer:

The equations are:

$4H + 3P = 13.75$

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Step-by-step explanation:

Let:

$H = hot\ dog$

$P =Pretzel$

For Tina:

$4H + 3P = 13.75$

For Doug:

$2H + 5P = 11.25$

Solving for the price of both items:

We have:

$4H + 3P = 13.75$ --- (1)

$2H + 5P = 11.25$ --- (2)

Multiply (2) by 2

2 * ( $2H + 5P = 11.25$ )

-------------------

$4H + 10P = 22.50$ --- (3)

Subtract (3) from (1)

$4H + 3P = 13.75$

$4H + 10P = 22.50$

----------------------

$4H - 4H + 3P - 10P = 13.75 - 22.50$

$3P - 10P = 13.75 - 22.50$

$-7P = -8.75$

Solve for P

$P = \frac{-8.75}{-7}$

$P = 1.25$

Substitute 1.25 for P in (2)

$2H + 5P = 11.25$

$2H + 5 * 1.25 = 11.25$

$2H + 6.25 = 11.25$

Collect Like Terms

$2H = 11.25-6.25$

$2H = 5$

Solve for H

$H = \frac{5}{2}$

$H = 2.50$

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