Answer:
11
Step-by-step explanation:
The average rate of change for the function f(x)= 3^x + 25 using the intervals of x=2 to x=6 is 6.75
The function is given as:
f(x) = 3^x + 25
The interval is given as:
x = 2 to 6
Start by calculating f(2) and f(6)
f(2) = 3^2 + 25 = 34
f(6) = 6^2 + 25 = 61
The average rate of change is then calculated as:
![m = \frac{f(6) - f(2)}{6 -2}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7Bf%286%29%20-%20f%282%29%7D%7B6%20-2%7D)
This gives
![m = \frac{61 - 34}{6 -2}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B61%20-%2034%7D%7B6%20-2%7D)
![m = \frac{27}{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B27%7D%7B4%7D)
m = 6.75
Hence, the average rate of change is 6.75
Read more about average rate of change at:
brainly.com/question/8728504
Answer: Answer choice: [A]: " x⁻ ⁴ " .
_____________________________________________
Step-by-step explanation:
_____________________________________________
Given:
{x ^
;
→ Simplify.
_____________________________________________
Note the following property of exponents:
_____________________________________________
→ (xᵃ) ᵇ = x ⁽ ᵃ * ᵇ ⁾ ; {a ≠ 0 ; b ≠ 0 .} .
_____________________________________________
As such:
_____________________________________________
→ {x ^
;
= x ^ (
;
_____________________________________________
Find:
" .
So: Find: "
" ;
The 2 (two) "7 's " ; cancel out to "1" ;
→ {since: " 7 ÷ 7 = 1 " } ;
And we have:
-4 * 1 = -4 .
So, we have:
" x ⁻ ⁴ " ; which is: Answer choice: [A]: " x⁻ ⁴ " .
___________________________________________
Choice: [C} — is also an equivalent; however, the question asks for the "simplest form" — which is: Answer choice: [A].
___________________________________________
The number is 778. hope this is right
\
Hey There!! ~
The answer to this is: the upper bound for the length is
Lower and Upper Bounds
The lower bound is the smallest value that will round up to the approximate value.
The upper bound is the smallest value that will round up to the next approximate value.
Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.
Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:
As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :
⇒ ![21.5cm.](https://tex.z-dn.net/?f=21.5cm.)
21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is
Hope It Helped!~
~