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aleksandrvk [35]
3 years ago
7

Graph the ellipse with equation x^2 /25 + y^2 /4 = 1.

Mathematics
1 answer:
nexus9112 [7]3 years ago
4 0
Center: 0,0
vertex: 5,0
vertex2 (-5,0)
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* ANSWER PLS TY!! * Find the surface area of this cone.
vagabundo [1.1K]

Answer:

<h2>200 \: \pi</h2>

Step-by-step explanation:

Given,

R = 8 m

H = 15 m

Slant height :

=  \sqrt{ {r}^{2}  +  {h}^{2} }

=  \sqrt{ {(8)}^{2} +  {(15)}^{2}  }

=  \sqrt{64 + 225}

=  \sqrt{289}

=  \sqrt{ {(17)}^{2} }

= 17 \: m

Now, Finding the surface area of the cone:

\pi \: r(r + s)

Plugging the values:

= \pi \:  \times 8(8 + 17)

= 8\pi \:  \times 25

= 200 \: \pi

Hope this helps...

Good luck on your assignment...

6 0
3 years ago
Samantha is a waitress and earns a weekly paycheck of $350 plus any tips she earns throughout the week. One week, Samantha notic
ss7ja [257]

Answer:(350+12x)/x

Step-by-step explanation:

First, you need to find the amount of money Samantha can earn throughout the week. This is represented by 12x+350

Then, divide that by the number of hours worked in a week (x).

Then, set it equal to 22 (the average hours worked).

3 0
3 years ago
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Rhianna has a spinner, which is divided into four equal parts. The parts are numbered 1, 2, 3, and 4. If Rhianna spins the spinn
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It takes 12 hours for a single hose to fill a large vat. When a second hose is added, the vat can be filled in 4 hours. How many
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<h3>Answer:</h3>

6 hours

<h3>Step-by-step explanation:</h3>

The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.

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The second hose alone can fill the vat in 6 hours.

_____

The first hose's rate of doing work is ...

... (1 vat)/(12 hours) = (1/12) vat/hour

If h is the second hose's rate of doing work, then working together their rate is ...

... (1/12 vat/hour) + h = (1/4 vat/hour)

... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour

... h = 1/6 vat/hour

so will take 6 hours to fill 1 vat.

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3 years ago
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18 units squared multiply 6 times 3 to get this answer- 18u^2
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