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Cloud [144]
3 years ago
12

No links please, will mark brainliest if the answer is correct and not a guess! Thank you so much.

Mathematics
1 answer:
sesenic [268]3 years ago
7 0
It is c because it adds 6 and minuses 2
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a car detailing company charges $30 plus $18 per hour. Another company charges $25 plus $20 per hour. What is a reasonable domai
Oxana [17]

Answer:

What is a reasonable domain for the two functions?

x > 0


5 0
4 years ago
How much?Please help me.
aniked [119]

Answer:

imma say $5300

Step-by-step explanation: if right plz mark as brainliest

sorry if wrong

8 0
3 years ago
Dilate line f by a scale factor of 2 with the center of dilation at the origin to create line f. Where are points A' and B' loca
V125BC [204]

Answer:

Option A

Step-by-step explanation:

We are given that

Scale factor=2

Center of dilation=(0,0)

Point A(0,2) and point B (2,0).

Slope of line f=\frac{y_2-y_1}{x_2-x_1}

Substitute the values

Slope of line f=\frac{0-2}{2-0}=-1

Distance between  A and Origin (0,0) is given by

OA=\sqrt{(0-0)^2+(0-2)^2}=2 units

Using distance formula

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

OB=\sqrt{(0-2)^2+(0-0)^2}=2 units

Length of OA'=2OA=2(2)=4 units

Length of OB'=2(OB)=2(2)=4 units

x-intercept of line f' at x=4

y-intercept of line f' at y=4

Therefore, the points A' and B' are given by

(0,4) and (4,0)

Slope of line f'=\frac{0-4}{4-0}=-1

Slope of line f and f' are equal.Therefore, lines f and f' are parallel.

Option A is true.

4 0
4 years ago
If f(x) = 2x2 + bx + c, find the value of "c" that makes the vertex of the given graph the same as the vertex of f(x).
AlekseyPX

Well it was a lucky guess but the answer is 75

8 0
4 years ago
Read 2 more answers
find the equation of the line using the point slope formula. write the final equation using the slope intercept for thr x-interc
aleksley [76]

we know the x-intercept of the line is 1, recall that an x-intercept is when the graph intercepts or touches the x-axis, and when that happens, y = 0, so the point is really x = 1, y = 0, namely (1,0). We also know another point on the line, is (-2, 9).


\bf \stackrel{x-intercept}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{0})}\qquad  (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9}) \\\\\\ slope =  m\implies  \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-0}{-2-1}\implies \cfrac{9}{-3}\implies -3 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-0=-3(x-1) \\\\\\ ~\hspace{10em}y=-3x+3

5 0
3 years ago
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