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Vikki [24]
4 years ago
5

Find the surface area of the regular pyramid shown to the nearest whole number. The figure is not drawn to scale.

Mathematics
2 answers:
Juli2301 [7.4K]4 years ago
7 0

Answer:

\text{The surface area is }351 m^2

Step-by-step explanation:

Given a regular pyramid we have to find the surface area of regular pyramid.

Side of base(regular hexagon)=13 m

Slant height=l=9 m

\text{Perimeter of regular hexagon=}13\times 6=78m

\text{Surface area=}\frac{1}{2}\times \text{perimeter of base}\times \text{slant height}

=\frac{1}{2}\times 78\times 9=351 m^2

Option A is correct.

sineoko [7]4 years ago
5 0

Answer:

Option D. 790 m²

Step-by-step explanation:

Surface area of the regular pyramid = surface area of hexagonal base + 6×Surface area of slant triangular side

Surface area of the hexagonal base = \frac{3\sqrt{3} }{2}(side)^{2}

= \frac{3\sqrt{3} }{2}(13)^{2}=\frac{(3)(169)\sqrt{3}}{2}

= 439 m²

Surface area of slant side = \frac{1}{2}(Base)(Height)=\frac{1}{2}(13)(9)

= 58.5 m²

Surface area of the pyramid = 439 + 6×58.5 = 439 + 351 = 790 m²

Option D. 790 m² is the answer.

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