Answer:
INF for first while D for second
Step-by-step explanation:
Ok I think I read that integral with lower limit 1 and upper limit infinity
where the integrand is ln(x)*x^2
integrate(ln(x)*x^2)
=x^3/3 *ln(x)- integrate(x^3/3 *1/x)
Let's simplify
=x^3/3 *ln(x)-integrate(x^2/3)
=x^3/3*ln(x)-1/3*x^3/3
=x^3/3* ln(x)-x^3/9+C
Now apply the limits of integration where z goes to infinity
[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]
[z^3/3*ln(z)-z^3/9]- (1/9)
focuse on the part involving z... for now
z^3/9[ 3ln(z)-1]
Both parts are getting positive large for positive large values of z
So the integral diverges to infinity (INF)
By the integral test... the sum also diverges (D)
Answer and Step-by-step explanation: With the constant velocity motion formula, we can determine constant velocity of the object in motion whose data we collected:
x = x₀ + vt
Velocity can be calculated as:


v = 3 m/s
The beginning of the data collect, object is 40m away, then x₀ = 40.
So, equation modeling the object's path is x = 40 + 3t.
Answer:
A
Step-by-step explanation:
Answer:
1/3
Step-by-step explanation:
Alright, so in this you want to use the slope formula: m=y2-y1/x2-x1. You plug the coordinates of the points into the formula to get the slope. (x1,y1) (x2,y2). So in this problem, 7 is x1, -1 is y1, -2 is x2, -4 is y2. So using the formula, you plug in y2 minus y1, divided by x2 minus x1.
So m (the slope) = -4- (-1) divided by -2-7.
2 negatives make a positive, so -4 + 1 is -3. -2-7 becomes -9. So this is now -3/-9. Again, 2 negatives make a positive, so this is now 3/9. Simplify and the answer is positive 1/3. Hope this helps!