Answer:
42
Step-by-step explanation:
The formula for area is length multiplied by width
7 X 6 = 42
hope this helps :)
We are given with two functions here: h(x) is 5^-x and g(x) is 5^x . we are asked in the problem to determine the value of the expression (g-h)(x). In this case, we just have to employ subtraction to the given functions. That is
(g-h)(x) = 5^x - 5^-x
= 5^x -1/5^x
= (5^2x -1)/5^x
Answer:
The quadratic equation is (x + 3)(x + 4) = 5
Step-by-step explanation:
If the degree of a polynomial is two then the polynomial is known as a quadratic.
Now, in the given equations we see which polynomial has a degree 2.
Simplify the first equation
![x(x^2+1)=0\\x^3+x=0](https://tex.z-dn.net/?f=x%28x%5E2%2B1%29%3D0%5C%5Cx%5E3%2Bx%3D0)
Degree is 3 and hence it is not a quadratic.
Take 2nd equation
![5(4x+2)=3\\20x+10=3](https://tex.z-dn.net/?f=5%284x%2B2%29%3D3%5C%5C20x%2B10%3D3)
Degree is 1 and hence it is not a quadratic.
Finally, we simplify the third equation
![(x+3)(x+4)=5](https://tex.z-dn.net/?f=%28x%2B3%29%28x%2B4%29%3D5)
Apply FOIL method to simplify the left hand side
![x^2+4x+3x+12=5=5](https://tex.z-dn.net/?f=x%5E2%2B4x%2B3x%2B12%3D5%3D5)
Degree is 2 and hence it is a quadratic equation.
Answer:
![-1/x^2](https://tex.z-dn.net/?f=-1%2Fx%5E2)
Step-by-step explanation:
First, let's simplify the expression on the right:
![1/\sqrt{x^2}=1/x](https://tex.z-dn.net/?f=1%2F%5Csqrt%7Bx%5E2%7D%3D1%2Fx)
Next, rewriting 1/x as x⁻¹, we can use the power rule to differentiate both sides with respect to x:
![y=x^{-1}\\dy/dx=d/dx(x^{-1})\\dy/dx=-x^{-2}=-1/x^2](https://tex.z-dn.net/?f=y%3Dx%5E%7B-1%7D%5C%5Cdy%2Fdx%3Dd%2Fdx%28x%5E%7B-1%7D%29%5C%5Cdy%2Fdx%3D-x%5E%7B-2%7D%3D-1%2Fx%5E2)
9514 1404 393
Answer:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
142 fish
Step-by-step explanation:
A) The differential equation is modified by adding a -50 fish per year constant term:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
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B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.
(0.4/1200)(N)(1200-N) -50 = 0
N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient
N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square
(N -600)^2 = 210,000 . . . . . simplify
N = 600 + √210,000 ≈ 1058
This steady-state number of fish is ...
1200 - 1058 = 142 . . . . below the original carrying capacity