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2 years ago

PLEASE ANSWER!!! WILL MARK BRAINLIEST!!!!!!!!

Mathematics

2 answers:

12345 [234]2 years ago

7 0

.75 he already traveled and .25 to go

tia_tia [17]2 years ago

4 0

Let 'x' represent the total distance from point A to point B

During the first hour he gets 0.25 of the way there: 0.25x

During the second hour he covers an additional 0.2 of the distance: 0.2x

During the third hour, he covers 0.3 of the distance: 0.3x

The total distance the biker traveled is:

0.25x + 0.2x + 0.3x = (0.25 + 0.2 + 0.3)x = 0.75x

The biker has: x - 0.75x = (1 - 0.75)x = 0.25x of the total distance left to go.

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Which equation represents the function graphed on the

Pavel [41]

Answer:

Step-by-step explanation:

sorry im late

8 0

2 years ago

Given that 1 kilogram weighs approximately 22 pounds, rewrite 10 pounds as an equivalent number of kilograms

yaroslaw [1]

Answer:

0.4545 kgs.

Step-by-step explanation:

Given that 1 kg weighs approximately 22 pounds.

i.e. 1kg= 22 lbs.

We can use this to convert lbs into kg.

22 lbs = 1 kg

Hence 1 lb = 1/22 = 0.04545 kg

Now to find out the equivalent weight for 10lbs,

we have conversion factor as 1 lb= 0.04545 kg

Hence 10 lbs = 10(0.04545) = 0.4545 kgs

Hence 10 pounds written in equivalent kgs would be0.4545 kgs.

4 0

2 years ago

Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

Yanka [14]

Answer:

$Range=14$

$\sigma^2 =32.4$

$\sigma = 5 .7$

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

$Data: 136, 129, 141, 139, 138, 127$

Solving (a): The range

This is calculated as:

$Range = Highest - Least$

Where:

$Highest = 141; Least = 127$

So:

$Range=141-127$

$Range=14$

Solving (b): The variance

First, we calculate the mean

$\bar x = \frac{1}{n} \sum x$

$\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)$

$\bar x = \frac{1}{6} *810$

$\bar x = 135$

The variance is calculated as:

$\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2$

So, we have:

$\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]$

$\sigma^2 =\frac{1}{5}*[162]$

$\sigma^2 =32.4$

Solving (c): The standard deviation

This is calculated as:

$\sigma = \sqrt {\sigma^2 }$

$\sigma = \sqrt {32.4}$

$\sigma = 5 .7$ --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

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2 years ago

2) find the volume of the trapezoid prism 7in 6in 4in 12in

JulsSmile [24]

Just here to get points sorry

3 0

2 years ago

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What is 33 over 55 and how do you simplify it.

Sergeu [11.5K]

$\frac{33}{55}= \frac{33\div11}{55\div11}=\boxed {\frac{3}{5} }$

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3 years ago

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