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3 years ago

One endpoint of a segment is (12, −8). the midpoint is (3, 18). find the coordinates of the other endpoint.

1 answer:

5 0

(-6,26) are the coordinates of the other endpoint because it it the same distance from the midpoint in the opposite direction of the other endpoint

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15m is what percent of 1.5km?

Papessa [141]

1.5km = 1500m
To find the percentage take 15 and divide it by 1500, then times by 100
15/1500 x 100 = 1%

3 0

2 years ago

What is 3/4 of 16/21? worked out please

timofeeve [1]

Of means multiplication

So

$\frac{3}{4} \sf{of} \frac{16}{21} = \frac{3}{4} \times \frac{16}{21}$

And then simplify the numerator ad denominator

= $\frac{3 \times 16}{4 \times 21} = \frac{\ 1 \times 16}{4 \times 7}$

And simplify the numerator and denominator again

= $\frac{\ 1 \times 16}{4 \times 7} = \frac{\ 1 \times 4}{1 \times 7}$

And we are finally left with the answer which is $\frac{4}{7}$

5 0

2 years ago

Please Please Please Help Me On These 2 Math Questions!!!!! I GIVE THANKS!!!!

Mars2501 [29]

A. After the mod. One wall is “x” longer than original (horizontal in diagram) and the other is “x” shorter (vertical)
(30+x)(30-x)

b. He original area = 30 x 30 = 900 sq. ft.
The mod. Area is (30+6)(30-6) = 36x24= 764 sq. ft.

So the room was largest to begin with when it was a square

3 0

2 years ago

You have $1200 to deposit into an account that pays 4.5% interest compounded continuously. How

Aloiza [94]

Answer:

The final balance is £1,720.

The total compound interest is £520

you don't even to round it at all

3 0

2 years ago

A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measures 42,000 ft2. What is a dimension of the

dalvyx [7]

To solve the problem we must know about quadratic equations.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

The breadth of the rectangle is 200 ft, while the length is 210 ft.

<h2>Explanation</h2>

Given to us

Area of the parking lot = 42,000 ft²
Perimeter of the parking lot = 820 ft

<h3>Area of the parking lot</h3>

Area of the parking lot = Area of the rectangle

42,000 ft² = Length x Breadth

Solving for L,

$42,000 = L \times B\\\\
L = \dfrac{42,000}{B}$

<h3>Perimeter of the parking lot</h3>

Perimeter of the parking lot = Perimeter of the rectangle

820 ft. = 2(Length + Breadth)

820 ft. = 2(L+ B)

$2(L+ B) = 820\\\\
(L+B) = \dfrac{820}{2}\\\\
(L+B) = 410$

Substituting the value of L,

$(L+B) = 410\\\\
(\dfrac{42,000}{B}) +B = 410\\\\
42000 + B^2 = 410B\\\\
B^2 -410B +42000 = 0$

<h3>Quadratic Expression</h3>

Solving the quadratic Expression,

$B^2 -410B +42000 = 0\\\\
(B-210)(B-200)=0$

Equation the factors against zero,

B-210=0

B = 210

B-200=0

B = 200

Hence, the breadth of the rectangle is 200ft, while the length is 210 ft.

Learn more about Quadratic Expression:

brainly.com/question/10025464

4 0

2 years ago