Answer:
Step-by-step explanation:
Given that:
X(t) = be the number of customers that have arrived up to time t.
... = the successive arrival times of the customers.
(a)
Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;




Now 
(b) We can Determine the conditional mean E[W3|X(t)=5] as follows;

Now; 
(c) Determine the conditional probability density function for W2, given that X(t)=5.
So ; the conditional probability density function of
given that X(t)=5 is:

Answer:
1/2 mile
Step-by-step explanation:
(1/8)*4 = 1/2 mile
Answer:
76.25°
Step-by-step explanation:
The solution to the differential equation is an exponential curve with a horizontal asymptote at Tm. It passes through (0, 145) and (30, 95), so the equation can be written as ...
T = 80 +65((95-65)/(145-65))^(t/30)
T = 80 +65(3/8)^(t/30)
That is, the temperature difference is reduced to 3/8 of its original value in 30 minutes.
Since the coffee in cup B cools twice as fast, it will cool to the same temperature (95°) in 15 minutes. In the next 15 minutes, the temperature difference will be reduced to (3/8)^2 of the original 80°, so will be 11.25°. That is, the temperature of cup B will be ...
11.25° +65° = 76.25°
after 30 minutes.
Answer:
prime factorization of 28
28 = 2 × 2 × 7
prime factorization of 50
50 = 2 × 5 × 5
Step-by-step explanation:
GCF, multiply all the prime factors common to both numbers:
Therefore, GCF = 2