What box should I check and what is the correct solution

Please help!!!!!!!!!!

horrorfan [7]

Answer:

sqrt 2

Step-by-step explanation:

4 0

2 years ago

Huilan's age is two times thomas's age. the sum of their ages is 84. what is thomas's age?

igomit [66]

H is 2t
h + t = 84
2t + t = 84
3t =84
t = 28
Thomas is 28 and huilan is 56

3 0

3 years ago

A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed

tresset_1 [31]

Answer:

a) $z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) $P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

c) $z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

$X \sim N(\mu = 34, \sigma=2.5)$

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

$P(34 < X$

We can find the number of deviation from the mean with the z score formula:

$z= \frac{X -\mu}{\sigma}$

And replacing we got

$z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

$P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

$P(29 < X$

And replacing we got:

$z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

7 0

3 years ago

How would you solve 3x^2-12=0?

Gennadij [26K]

   3x^2 - 12 = 0

Personally, I would divide each side by 3 x^2 - 4 = 0

Then I would add 4 to each side x^2     = 4

Then I would take the square root of each side: x = +4
   x = -4 .

Having found both solutions, I would relax with a cup of tea.

3 0

3 years ago

Once the Mercury-Atlas 9 was in orbit, in the first 20 seconds the spacecraft traveled 156km. What was the acceleration of the s

Shkiper50 [21]

Spacecraft once the 20 seconds space

6 0

3 years ago