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3 years ago

Write the sum using summation notation, assuming the suggested pattern continues.

Mathematics

1 answer:

Lyrx [107]3 years ago

8 0

Answer:

second sum

Step-by-step explanation:

Note the given terms are perfect cubes, that is

343 = 7³

512 = 8³

729 = 9³

1000 = 10³

The sequence continues in this way as indicated by the dots ......

The first term is 343 and occurs when n = 7

The sequence is infinite, thus can be expressed as

∑ n³ from n = 7 to infinity

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Factor the polynomial by grouping. 12x^x+x−13

tekilochka [14]

Answer:

(x -1)(12x +13)

Step-by-step explanation:

You are looking to rewrite the middle term as the sum of terms that have factors of (12)(-13) that have a total of +1. Those factors are -12 and +13, so the expression you are factoring by grouping is ...

12x^2 +13x -12x -13

= x(12x +13) -1(12x +13)

= (x -1)(12x +13)

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3 years ago

A company is expanding its building area from 17000 square feet to 24480 square feet. What is the percentage increase of the are

Ulleksa [173]

I would say A because 1700-24480 is -74.8%

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3 years ago

Wha is 5÷312 in long division

bezimeni [28]

The answer is 62 with a remainder of 2.

Hope this helps!

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3 years ago

A textbook has 428 numbered pages, starting with 1.

kolezko [41]

Answer:

1/428 or 0.00233644859% chance

Step-by-step explanation:

Simply because there is only one page 45 use 428 as your denominator and then divide 1 by 428!

5 0

2 years ago

Read 2 more answers

Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

natima [27]

$\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0$

$\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}$

5 0

3 years ago