The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
Answer:
2(x+4) + 2(2x-7) = 42 ( If this is wrong simplify this)
Step-by-step explanation:
The formula for perimeter is (2 x length) + (2 x width), so our equation would be 2(x+4) + 2(2x-7) = 42
33,52 Thats what i think at least
Answer:
x intercepts are (4,0) and (-6,0)
axis of symmetry is x=-1
vertex is (-1,-25)
Step-by-step explanation: