C
explanation:
6(1)-39=-33
6(2)-39=-27
Answer:
i belive its 75 percent
Step-by-step explanation:
the question is worded strangly
Answer: 109 years old
Step-by-step explanation:
2009-1900=109
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
Step-by-step explanation:
Let x, y , and z be the numbers.
Then the geometric sequence is 
Recall that term of a geometric sequence are generally in the form:
This implies that:
a=32 and 
Substitute a=32 and solve for r.
Take the fourth root to get:
![r=\sqrt[4]{\frac{81}{256} }](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B81%7D%7B256%7D%20%7D)
Therefore 
