Answer:
Probability that a marble drawn at random is not red = .
Step-by-step explanation:
Given : A jar contains 3 red, 4 blue, and 2 white marbles.
To find : What is the probability that a marble drawn at random is not red.
Solution : We have given that
Red marbles = 3.
White marbles = 2.
Blue marbles = 4
Total marbles = 9
Marbles that are not red = white + blue =2+4 = 6.
Probability that a marble drawn at random is not red = .
Probability that a marble drawn at random is not red = .
Probability that a marble drawn at random is not red = .
Therefore, Probability that a marble drawn at random is not red = .
Answer:
30 blue pins
Step-by-step explanation:
30% is the same as 30 out of 100, so this can be written in this fraction:
now, you should multiply this fraction by the total number of pins she ordered:
100 x
to solve this, you can simplify by dividing 100 by 100, this equals 1
30 times 1 is 30
there are 30 blue pins
Answer:
Step-by-step explanation:
1) Mark two points on the line in the graph.
2) Determine the rise and run. Rise ---> difference in y-coordinates. (y2-y1)
Run -----> difference in x-coordinates (x2 - x1)
3) Plugin the values in the below mentioned formula.
1.If slope = 0, then the line is parallel to x-axis.
2. If slope is undefined, then the line is parallel to y-axis.
3. If slope is +ve, then the line slant upwards and if slope = -ve, then the line slant downwards.
Answer:
∠EFD ≅ ∠EGD ⇒ A
Arc ED ≅ arc FD ⇒ C
m arc FD = 120° ⇒ E
Step-by-step explanation:
Let us revise some facts
In the quadrilateral CDGE
∵ m∠G = 60°
∵ m∠GDC = m∠GEC = 90°
- By using the 5th rule above
∴ m∠G + m∠GDC + m∠DCE + m∠GEC = 360°
∴ 60 + 90 + m∠DCE + 90 = 360
∴ 240 + m∠DCE = 360
- Subtract 240 from both sides
∵ m∠DCE = 120°
In circle C
∵ ∠DCE is a central angle subtended by arc DE
∵ ∠DFE is an inscribed angle subtended by arc DE
- By using the 2nd rule above
∴ m∠DFE = m∠∠DCE
∵ m∠DCE = 120°
∴ m∠DFE = (120)
∴ m∠DFE = 60°
- That means ∠EFD ≅ ∠EGD because their measure is 60°
∴ ∠EFD ≅ ∠EGD
In Δ EFD
∵ EF = FD
∵ m∠DFE = 60°
- By using the 4th rule above
∴ Δ EFD is an equilateral triangle
∴ ED = FD = FE
In circle C
∵ Side ED subtended by arc ED
∵ Side FD subtended by FD
∵ Side ED ≅ side FD ⇒ proved
- By using the 1st rule above
∴ Arc ED ≅ arc FD
∵ m∠ECD = 120°
∵ ∠ECD is a central angle subtended by arc ED
- By using the 3rd rule above
∴ m∠ECD = m arc ED
∴ m of arc ED = 120°
∵ Arc ED ≅ arc FD
∴ m arc ED = m arc FD
∴ m arc FD = 120°