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2 years ago

Evaluate the expression for p = 3. 5p =

Mathematics

1 answer:

Goryan [66]2 years ago

4 0

5p = 15

5 multiplied by 3 equals 15

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Solve for y hdgkgsydkydutskgxtisit

Feliz [49]

You said X = (5y+1) / (y-2)

Multiply each side by (y-2):

X(y-2) = (5y+1)

Eliminate parentheses:

Xy - 2X = 5y + 1

Add 2X to each side:

Xy = 5y + 1 + 2X

Subtract 5y from each side:

(X-5)y = 1 + 2X

Divide each side by (X-5):

7 0

2 years ago

Read 2 more answers

What is the dimension of a rectangle if the perimeter is 198

AfilCa [17]

Answer:

Length = 49.5 unit and width = 49.5 unit

Step-by-step explanation:

Given as , Perimeter of rectangle = 198 unit

so ,as Perimeter of rectangle = 2× ( Length + width)

Or, 198 = 2 × (Length + width)

Or, $\frac{198}{2}$ = length + width

So, length + width = 99 unit

Now to make area maximum

Length × width = maximum

Or, (99 - width ) × width = maximum

99 Width - width² = maximum Let width = W

Now differentiate both side with respect to W

D(99W - W²) $\frac{D(99w - w^2)}{Dw}$ = 0 as, constant diff is 0

So, 99 - 2w = 0

Or, w = $\frac{99}{2}$

Or, w = 49.5 unit and L = 99- 4905 = 49.5 unit Answer

3 0

2 years ago

( − 35 − 42 − 63 ) ∶ ( + 7 )

olga nikolaevna [1]

(-35-42-63)/7= (-140)/7=-20

7 0

2 years ago

Find the value of the expression 6x + 3xy, when x = 2 and y = 4.

damaskus [11]

<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Substitute in the values:

6(2) + 3(2)(4)

Now just solve:

12 + 24 = 36

The answer is 36

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0

3 years ago

Read 2 more answers

It is possible to get 2 solutions when the system of equations is: (check all that apply)

SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as $x^2+ y^2 = 1$ ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

$x^2 + x^2 = 1\\2x^2 = 1\\$

$x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$ so Y = $+\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$

so the two solution are ( $(\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} }$ )

A system of the equation of a parabola and a linear equation

Let equation of Parabola be $y^2 = x$

and linear equation y = x

substitute

$x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1$

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0

2 years ago