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Elenna [48]
3 years ago
13

-5x +7=-38 please help meee

Mathematics
2 answers:
Sedaia [141]3 years ago
7 0

Answer:

-5x+7=-38

-5x=-45

x=9

Step-by-step explanation:

Wittaler [7]3 years ago
6 0
-5x + 7 = -38
-5x - 7 = -38
-5x = -45
/-5 x = -45
x= -9

Thus, x= -9


Hope this helps :)
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When we use arcsine, we are finding the angle while giving the trigonometric ratio.

Arcsin(u) = theta can be rewritten as:

sin(theta) = u

Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.

We can use Pythagorean Theorem to find the adjacent (x value).

1^2 - u^2 = x^2

x = sqrt(1-u^2)

Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).

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Or just sqrt(1-u^2)







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The heights in cm of some pupils are
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If f(x) = 4x – 3 and g(x) = x + 4, find (f – g)(x).
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<span>C. 5x – 1 im possitive</span>
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Answer:

2

Step-by-step explanation:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}

\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}

3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}

This implies

x+2=4

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-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

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