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lukranit [14]
3 years ago
12

TV studio has brought in 9 boy kittens and 6 girl kittens for a cat food commercial. The director is going to choose 9 of these

kittens at random to be in the commercial. What is the probability that the director chooses 5 boy kittens and 4 girl kittens? Round your answer to three decimal places.
Mathematics
1 answer:
Amanda [17]3 years ago
6 0

Answer:

probability = 0.2517

Step-by-step explanation:

given data

boy kittens = 9

girl kittens = 6

choose kittens at random = 9

solution

total kitten are = 9 + 6 = 15

first we get here total no of probability that is

n(s) = 15 C 9

n(s) = \frac{15!}{9!(15-9)!}  

n(s) =5005

and

total way to chose 5 boy kittens is = 9 C 3

n(3) = \frac{9!}{3!(9-3)!}  

n(3) =  84

and

total way to chose 4 girl kittens is = 6 C 4

n(4) = \frac{6!}{4!(6-4)!}  

n(4) = 15

so

total way to chose 5 boy kittens and 4 girl kittens is

total way = 84 ×15  = 1260

so probability that the director chooses 5 boy kittens and 4 girl kittens is

probability = \frac{1260}{5005}  

probability = 0.2517

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