Question

Suppose two data segments with byte sequence numbers 3000 and 15000 are lost once during the transmission. How many segments get retransmitted under each of the following conditions? A. Round trip time = 100 ms, Timeout = 101 ms

Answer 1

Answer:

The solution for the given question is described below.

Explanation:

For the corresponding case, the estimated number of the section is a follow:

If,

Round trip = 100 ms

Time out = 101 ms

then,

Segments number = $\frac{300}{100} =30$

and, $\frac{15000}{100}=150$

Thus,

The total amount of segments = 150+30 = 180 Segments.

Segment number Timeout = 180-101 = 179 Segments.