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lys-0071 [83]
3 years ago
9

PLEASE ANSWER ASAP

Computers and Technology
2 answers:
kompoz [17]3 years ago
3 0
D, an acrostic is a "a poem, word puzzle, or other composition in which certain letters in each line form a word or words."
Shkiper50 [21]3 years ago
3 0

Solution:

The correct answer is C.

It's mnemonic device.

Acrostic is a poem (or other form of writing) in which the first letter (or syllable, or word) of each line (or paragraph, or other recurring feature in the text) spells out a word, message or the alphabet The word comes from the French acrostiche from post-classical Latin acrostichis, from Koine Greek from Ancient Greek the "highest, topmost" is a form of constrained writing, an acrostic can be used as a mnemonic device to aid memory retrieval. crostics are common in medieval literature, where they usually serve to highlight the name of the poet or his patron, or to make a prayer to a saint. They are most frequent in verse works but can also appear in prose. The Middle High German poet Rudolf von Ems for example opens all his great works with an acrostic of his name, and his world chronicle marks the beginning of each age with an acrostic of the key figure (Moses, David, etc.).

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The game begins with the player having 20 POINTS
kompoz [17]

Answer:

Following are the code to this question:

import random#import package for using random method  

def rolling_dice(): #defining method rolling_dice that uses a random number to calculate and add value in dice1 and dice2 variable

   dice1 = random.randint(1,6)

   dice2 = random.randint(1,6)

   return dice1 + dice2

def rolling(): # defining method rolling

   n_roll = 0  # defining num variable that initial value that is 0.

   p = 20 # defining variable p for looping, that points in between 1 and 59

   while p > 0 and p < 60: # defining loop that counts value dice value two times  

       d = rolling_dice()#defining d variable that hold method value

       n_roll+= 1 #defining n_roll that increment n_roll value by 1

       if d == 7 or d == 11:# defining if block that uses the d variable that checks either 7 or 11, player won d in p variable

           p+= d   # use p variable that adds d variable

       elif d == 2 or d == 3 or d == 12:#defining elif block to that checks d variable by using or operator  

           p-= d#defining d variable that decreases d variable variable

       else: # defining else block

           p1 = d # using p1 variable that store d value  

           while True:# defining loop that calculates values

               d = rolling_dice()#defining d variable that holds method values

               n_roll += 1 #increment the n_roll value by 1

               if d == 7:#defining if block that checks d value equal to 7

                   p -= p1#subtract the value of p1 in p variable  

                   break # exit loop

               elif d == p:#defining elif block to check d value is equal to p

                   p += p1#adds the value of p1 in p variable  

                   break#using break keyword

   if p<= 0:#defining if block that checks p-value is less then equal to 0  

       print('Player lost')#using print method

   elif p>= 60:#defining else block that checks p-value is greater than equal to 60

       print('Player won')#using print method to print the value

   print('number of dice rolls:', n_roll)#use print method to print n_rolls value

rolling()

Output:

Player lost

number of dice rolls: 38

Explanation:

In the above-given python code, a method "rolling_dice" is declared, inside the method two-variable "dice1 and dice2" is declared, that uses the random method to calculate the value in both variable and use the return keyword to add both values.

  • In the next step, another method the "rolling"  is declared, inside the method "n_roll and p" is declared that assigns the values and use the two while loop, inside the loop if block is defined that calculates the values.
  • In the next step, a condition block is used that stores value in the p variable and use the print method to print the "n_roll" value.  
8 0
3 years ago
Hi I paid for brainy plus, but it says the it can't renew and try paying for it again but it won't work. Please help
Scorpion4ik [409]

Answer:

Contact CS, ( customer support ) They should be able to help you. Go to this link for more info. brainly.com/contact/index

Explanation:

8 0
3 years ago
On a printed circuit board, electronic components will be mounted from the
Likurg_2 [28]
On a printed circuit board, electronic parts will be mounted from the substrate side of the board. The leads jab through the substrate and the copper sheeting that has been carved. The leads are then soldered to the copper.

I hope the answer will help you. 
3 0
3 years ago
Why might a peer-to-peer network not be the best choice for a large corporate office setting?
omeli [17]

Answer:

a it is less private

Explanation:

8 0
3 years ago
Spoderman memes<br> im scared-
DENIUS [597]

Don't be afraid of spooderman. He's hot.

4 0
3 years ago
Read 2 more answers
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