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Alik [6]
3 years ago
15

A rectangle has a length of 28 inches and a diagonal that measures 35 inches. What is the area, in square inches, of the rectang

le?
Mathematics
2 answers:
butalik [34]3 years ago
7 0

Answer:

588 in²

Step-by-step explanation:

length: 28 inches

height: a

hypotenuse: 35 inches

Pythagorean Theorem: a² + b² = c²

a² + 28² = 35²

a² + 784 = 1225

a² = 441

a = \sqrt{441}

a = 21 inches

Area of rectangle: Length x Width

28 x 21 = 588 in²

Natali5045456 [20]3 years ago
6 0

Answer:

28x35=980

Step-by-step explanation:

area of the rectangle= base (28) by height (35)

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Which expression could be represented by this model? Check all that apply.
svetoff [14.1K]

Answer:

8=8

Step-by-step explanation:

jgvbhytrjhfr5tfhtftvygftvggfgfgvgbfyt

5 0
3 years ago
At a college there are 120 freshmen, 90 sophomores, 110 juniors, and 80 seniors. A school administrator selects a random sample
murzikaleks [220]

Answer:

Stratified sampling

Step-by-step explanation:

The is a type of sampling in which the population of interest is divided into subpopulations and then each subpopulation is randomly sampled.

In this case study, instead of just doing a random sampling of all students, the research divided the population of all students into subpopulations which includes freshmen, sophomores, juniors and seniors and then she makes a random sampling of each of these subpopulations.

4 0
3 years ago
Solve the system of equations.
emmainna [20.7K]

x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }

<h2>Explanation:</h2>

We have the following system of three linear equations:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\5~ x&+~~8~ y&+~~~~ z&~=~4\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}

Let's use elimination method in order to get the solution of this system of equation, so let's solve this step by step.

Step 1: Multiply first equation by -5/2 and add the result to the second equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}

Step 2: Multiply first equation by −2 and add the result to the third equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&-~~~3~ y&-~~~62~ z&~=~-6\end{array}

Step 3: Multiply second equation by −32 and add the result to the third equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&&+~~\frac{ 113 }{ 2 }~ z&~=~\frac{ 21 }{ 2 }\end{array}

Step 4: solve for z.

\begin{aligned}       \frac{ 113 }{ 2 } ~ z & = \frac{ 21 }{ 2 } \\      z & = \frac{ 21 }{ 113 }       \end{aligned}

Step 5: solve for y.

\begin{aligned}-2y-79z &= -11\\-2y-79\cdot \frac{ 21 }{ 113 } &= -11\\y &= -\frac{ 208 }{ 113 } \end{aligned}

Step 6: solve for x by substituting y=-\frac{208}{113} and z = \frac{21}{113} into the first equation:

2x+4(-\frac{208}{113})+32(\frac{21}{113})=6 \\ \\ 2x-\frac{832}{113}+\frac{672}{113}=6 \\ \\ 2x=6+\frac{832}{113}-\frac{672}{113} \\ \\ 2x=\frac{838}{113} \\ \\ x=\frac{319}{113}

Finally:

x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }

<h2>Learn more:</h2>

Solving System of Equations: brainly.com/question/13121177

#LearnWithBrainly

7 0
4 years ago
brandon has a collection of 25 pair of jordans and adidas shoes the average cost for the jordans are $165 while the average cost
Evgen [1.6K]

Answer:

Step-by-step explanation:

Guess and Check:

$80.00*15=$1,200

$165.00*10=$1,650

$1,200+$1,650=$2,850.

15 of the pairs of shoes are Jordans, while 10 of the pairs are Adidas.

5 0
3 years ago
After riding her bike for 20 miles. Angela got off and walked her bike the rest of the way at 5 miles per hour. If the total tri
mylen [45]

Answer:

She rode her bike 20 miles... I believe this may be a trick question.

Step-by-step explanation:

Let's break down this problem...

If she is going at a rate of 5 miles per hour while walking than the maximum she could have walked in 5 hours is 25 miles.

If Angela rode her bike for 20 miles, and the got off her bike and walked "<em>the rest of the way</em>" then she should have walked 50 miles. However as we already know her rate is 5 miles per hour while walking, and therefore could only have covered half that distance in 5 hours.

Is this a multiple choice question? Is there any misssing informaation?

7 0
3 years ago
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