<span>solve -2(2x + 5) - 3 = -3(x - 1)
-4x - 10 -3 = -3x + 3
-4x - 13 = -3x + 3
Add 3x to both sides
-4x - 13 +3x = -3x +3
Simplify
-x - 13 = 3
Add 13 to both sides
-x - 13 + 13 = 3 + 13
Simplify
-x = 16
multiply both sides by (-1)
x = -16</span>
For a better understanding of the explanation provided here kindly go through the file attached.
Since, the weight attached is already at the lowest point at time, t=0, therefore, the equation will have a -9 as it's "amplitude" and it will be a Cosine function. This is because in cosine function, the function has the value of the amplitude at t=0.
Now, we know that the total angle in radians covered by a cosine in a given period is
and the period given in the question is t=3 seconds. Therefore, the angular velocity,
of the mentioned system will be:

Combining all the above information, we see that the equation which models the distance, d, of the weight from its equilibrium after t seconds will be:

Thus, Option B is the correct option. The attached diagram is the graph of the option B and we can see clearly that at t=3, the weight indeed returns to it's original position.
Answer:
-1.5
Step-by-step explanation:
Answer:
12 minutes I think question kinda confusing