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marissa [1.9K]
3 years ago
8

5/6,3/8 The LCD is 2 24 48

Mathematics
1 answer:
pentagon [3]3 years ago
6 0
<h3>The least common denominator is 24</h3>

<em><u>Solution:</u></em>

Given that,

\frac{5}{6} , \frac{3}{8}

We have to find the least common denominator

The denominators are 6, 8

List all prime factors for each number.

Prime Factorization of 6 is:

2 x 3  

Prime Factorization of 8 is:

2 x 2 x 2

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

2, 2, 2, 3

Multiply these factors together to find the LCM

LCM = 2 x 2 x 2 x 3 = 24

Thus the least common denominator is 24

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A taxi driver had 29 fares to and from the airport last Monday. The price for a ride to the airport is $4.50, and the price for
Serhud [2]

Answer:(12,17)

Step-by-step explanation:

X + y= 29

4.50x + 7y=173

Solve by elimination.

5 0
3 years ago
Assume that in a particular military exercise involving two units, Red and Blue, thereis a 60 % chance that the Red unit will su
Marysya12 [62]

Answer: a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%

Hence, there are 88% chances that one or the other but not both of the units will be successful.

6 0
3 years ago
Help please anyone pleaseeeeeeeee
Rainbow [258]
The answer is D. The height gets very small
4 0
4 years ago
Explain how you know if an equation has no solutions, one solution or an infinite number of solutions
topjm [15]

Answer:

If you cancel out all of the x terms via addition or subtraction, and you get something along the lines of 1 = 2, then you have no solution.

11x + 4 = 11x + 7 Subtract 11x from both sides

4 = 7 No value for x will satisfy this equation.

If you cancel out all the x terms via addition or subtraction and you get something along the lines of 1 = 1, then you have infinite solutions.

2(x + 1) = 2x + 2 Expand the left side using the distributive property

2x + 2 = 2x + 2 Subtract 2x from both sides

2 = 2 Every value for x will satisfy this equation

If you can’t cancel out all the x terms with addition or subtraction, you probably have 1 solution.

5x + 2 = 3x + 100 Subtract 3x from both sides

2x + 2 = 100 Subtract 2 from both sides

2x = 98 Divide by 2 on both sides

x = 49 The only x value that satisfies this equation is 49

There are other cases where functions of x aren’t injective, meaning there’s more than one x value that satisfies the equation. Here’s what I mean.

x^2 = 4

x = 2 or -2

x^3 = 1

x = 1, -1/2 + isqrt(3)/2, -1/2 - isqrt(3)/2

sin(x) = 0

x = 2n*pi, where n is some integer

5 0
3 years ago
mr.roxbury weighed 240 pounds when he started on a diet. over a one year period mr.roxbury lost 32% of his body weight. in the f
Annette [7]

Answer:

187.68

Step-by-step explanation:

240*.32=76.8

240-76.8=163.2

163.2*.15=24.48

163.2+24.48=187.68

3 0
3 years ago
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