Answer:
the answer is C
Step-by-step explanation:
A) 3x (you substitute the g equation into the f one by putting it in the x value for f)
b) x (do the same thing, but switch the letters)
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
a) Scores of 2 and higher are significantly high
b) Scores of -2 and lower are significantly low
c) Scores between -2 and 2 are not significant.
Step-by-step explanation:
Mean = 0
Standard deviation = 1
a. significantly high (or at least 2 standard deviations above the mean).
2 standard deviations above the mean is:
0 + 1*2 = 2
So scores of 2 and higher are significantly high
b. significantly low (or at least 2 standard deviations below the mean).
2 standard deviations below the mean is:
0 - 1*2 = -2
So scores of -2 and lower are significantly low
c. not significant (or less than 2 standard deviations away from the mean).
2 standard deviations above the mean is:
0 + 1*2 = 2
2 standard deviations below the mean is:
0 - 1*2 = -2
So scores between -2 and 2 are not significant.
Answer:
can u translate in english
Step-by-step explanation:
