Answer:
No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.
Step-by-step explanation:
1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.
The Range Δ is calculated:
Maximum value - Minimum value for weight
Mean:
Variance:
The Standard Deviation of the sample
2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),
Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.
Answer:
I Do
Step-by-step explanation:
Answer:
✔️The measure of angle <CBA is equal to the measure of angle <DBE.
✔️The measure of angle CBD is equal to the measure of angle ABE.
✔️The sum of the measures of angles CBD and CBA is 180 degrees.
Step-by-step explanation:
Vertical angles are formed when two straight lines intersect each other at a certain point. The diagram given is a typical example. This, vertical opposite angles formed are said to be congruent, that is their measures are equal to each other.
The following statements are true of the given diagram:
✔️The measure of angle <CBA is equal to the measure of angle <DBE.
(<CBA and ,<DBE are vertically opposite angles)
✔️The measure of angle CBD is equal to the measure of angle ABE.
(They are both vertically opposite angles)
✔️The sum of the measures of angles CBD and CBA is 180 degrees.
(<CBA and <CBD are supplementary angles)
Difference would be 1000x3.0 - 8.8x10000 = -85000
Scientific notation would be 8.5x10^-4
Answer and Step-by-step explanation:
If we put 
into decimal form, we get -0.45.
-0.45 is greater than -0.5, so,
<u></u><u> is greater than -0.5.</u>
<u></u>
<u></u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
