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Aleks [24]
3 years ago
11

PLEASE HELP IM STUCK... How do you find the length of CD?

Mathematics
2 answers:
evablogger [386]3 years ago
8 0

what math class is this

pogonyaev3 years ago
6 0
You have to complete the first one(abc) then go and do acd so find all the measurements for abc first
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Can someone help me with this question please?
Kaylis [27]

Answer:

-2,-1,0,1

Step-by-step explanation:

-5 ≤x≤1   and 1 ≤x+3<8

For the first statement

-5 ≤x≤1

The integers are -5,-4,-3,-2,-1,0,1

For the second

1 ≤x+3<8

Subtract 3 from all sides

1-3 ≤x+3-3<8-3

-2 ≤x<5

The integers are

-2,-1,0,1,2,3,4  ( does not include 5 since there is no equal)

There is an and between the statements so it has to be in both

-5,-4,-3,-2,-1,0,1

-2,-1,0,1,2,3,4

The numbers in both are

-2,-1,0,1

4 0
4 years ago
Line A passes through the points (-1, 4) and (4, 9). Line B passes through the points (4, -4) and (-3, 24). Find the point where
exis [7]
A calculator can help
7 0
3 years ago
Read 2 more answers
Solve each equation. I don't know this
MArishka [77]
1.(2x - 3)(x + 7) = 0
   2x^{2} + 14x - 3x - 21 = 0                                  
   2x^{2} + 11x - 21 = 0                       
  
   x = \frac{-11 +/- \sqrt{11^{2} - 4(2)(-21)}}{2(2)}                 
  
   x = \frac{-11 +/- \sqrt{121 + 168}}{4}
  
   x = \frac{-11 +/- \sqrt{289}}{4}
  
   x = \frac{-11 +/- 17}{4}
  
   x = -2.75 +/- 4.25
   x = -2.75 + 4.25                     x = -2.75 - 4.25
   x = 1.5                                                   <u></u>x = -7
----------------------------------------------------------------------------------------------------------  2.8x(2x - 5) = 0
   8x(2x) - 8x(5) = 0
   16x^{2} - 40x = 0
   16x^{2} - 4x + 0 = 0
  
   x = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4(16)(0)}}{2(16)}
  
   x = \frac{40 +/- \sqrt{1600 - 0}}{32}
  
   x = \frac{40 +/- \sqrt{1600}}{32}
  
   x = \frac{40 +/- 40}{32}
  
   x = 1.25 +/- 1.25
   x = 1.25 + 1.25                                  x = 1.25 - 1.25
   x = 2.5                                               x = 0
----------------------------------------------------------------------------------------------------------
3.x^{2} + 3x - 10 = 0
  
   x = \frac{-3 +/- \sqrt{3^{2} - 4(1)(-10)}}{2(1)}
  
   x = \frac{-3 +/- \sqrt{9 + 40}}{2}
  
   x = \frac{-3 +/- \sqrt{49}}{2}
  
   x = \frac{-3 +/- {7}}{2}
  
   x = -1.5 +/- 3.5
   x = -1.5 + 3.5               x = -1.5 - 3.5
   x = 2                             x = -5
----------------------------------------------------------------------------------------------------------
4. x^{2} = 13x - 36
    x^{2} - 13x + 36 = 13x - 13x - 36 + 36
    x^{2} - 13x + 36 = 0
   
    x = \frac{-(-13) +/- \sqrt{(-13)^{2} - 4(1)(36)}}{2(1)}

   
    x = \frac{13 +/- \sqrt{169 - 144}}{2}
  
    x = \frac{13 +/- \sqrt{25}}{2}
 
    x = \frac{13 +/- 5}{2}

    x = 6.5 +/- 2.5
    x = 6.5 + 2.5                     x = 6.5 - 2.5
    x = 9                                 x = 4
----------------------------------------------------------------------------------------------------------
5.3x^{2} - 7x + 2 = 0
  
   x = \frac{-(-7) +/- \sqrt{(-7)^{2} - 4(1)(2)}}{2(3)}

   x = \frac{7 +/- \sqrt{49 - 8}}{6}

   x = \frac{7 +/- \sqrt{41}}{6}

   x = \frac{7 +/- 6.403124237432849}{6}
 
   x = 1.167+/- 1.06718737290547
   x = 1.67 + 1.06718737290547              x = 1.167 - 1.06718737290547
   x = 2.73718737290547                         x = 0.60281262709453
----------------------------------------------------------------------------------------------------------
6.10x^{2} - 10x + 9 = 5x^{2} + 4x + 1
   10x^{2} - 5x^{2} - 10x + 10x + 9 - 1 = 5x^{2} - 5x^{2} + 4x + 10x + 1 - 1
   5x^{2} + 8 = 14x
   5x^{2} - 14x + 8 = 14x - 14x
   <u />5x^{2} - 14x + 8 = 0
  
   x = \frac{-(-14) + \sqrt{(-14)^{2} - 4(5)(8)}}{2(5)}
  
   x = \frac{14 +/- \sqrt{196 - 160}}{10}
  
   x = \frac{14 +/- \sqrt{36}}{10}.
  
   x = \frac{14 +/- 6}{10}
  
   x = 1.4 +/- 0.6
   x = 1.4 + 0.6                x = 1.4 - 0.6
   <u />x = 2                            x = 0.8
 
 
5 0
4 years ago
Jenny's great grandmother is 90 years old. Jenny is 12 years old, what percent of Jenny's great-grandmother's age is Jenny's age
user100 [1]
90x = 12
Divide both sides by 90

x = 0.1333....

Move the decimal to places to the right.
13.333% repeating.
3 0
4 years ago
Read 2 more answers
How to divide fractions with concrete models? PLEEASE I HAVE A TEST TOMORRW, I WILL GIVE FIRST ANSWER THAT IS SMART BRANLIEST
Leya [2.2K]

Answer:

So first, there is an acronym for the strategy, KFC.

°π°

Keep the first fraction. Ex, 4/5 ÷ 1/5

Flip the second fraction. Ex, 4/5 ÷ 5/1

Change symbol. Ex, 4/5 ÷ 5/1 turns into 4/5<em>x</em>5/1

8 0
3 years ago
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