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Lelu [443]
4 years ago
6

Write an equation of the line passing through the points (4,10) and (-1,-15)

Mathematics
1 answer:
KATRIN_1 [288]4 years ago
3 0

Answer:

Step-by-step explanation:

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6•[4 -2 1]<br> [7 3 0]<br><br> Its on edg!
grandymaker [24]
6 because it’s the right answer
7 0
4 years ago
What does a equal? a/15 = 4/5?
ratelena [41]
So in order to solve this we are going to cross multiply:
 a     4
--- = --
15    5   so what were are going to do is we will take a and multiply it with 5 and we will take 15 and multiply it with 4. Now this gives us 5a and 60 so our new equation is:
5a = 60 now we are going to get our variable alone by dividing it by 5 and what we do on one side of the equation we do on the other:
5a = 60
÷5    ÷5 this gives us a=12
hope this answer helps
6 0
4 years ago
Read 2 more answers
A survey found that 25% of pet owners had their pets bathed proffesionally rather than doing it themselves. If 18 pet owners are
AveGali [126]
The probability is 19.88%.

This is a binomial distribution, because there are two outcomes, the events are independent of each other, and there is a fixed number of trials.  The binomial distribution is given by:

(_k^n)p^k(1-p)^{n-k}

For this, n is 18; k is 5; p is 0.25:
(_5^{18})(0.25)^5(1-0.25)^{18-5}&#10;\\&#10;\\=\frac{18!}{5!13!}(0.25)^5(0.75)^{13}&#10;\\&#10;\\=8568(0.25)^5(0.75)^{13}&#10;\\=0.1988=19.88%
8 0
3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
I need help please i would appreciate it​
Reptile [31]
Answer: 5/3

i hope that’s correct :)
3 0
3 years ago
Read 2 more answers
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